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3 years ago

Magnesium is a highly flammable element which is easily combustible in the presence of oxygen:

Physics

2 answers:

Juli2301 [7.4K]3 years ago

7 0

Answer:

Explanation:

4 atoms would be produced, since the reactants are 2 atoms of magnesium and 1 molecule of diatomic oxygen (which contains 2 atoms). Due to the law of conservation of matter, the total number of atoms can not increase or decrease in a chemical reaction.

NemiM [27]3 years ago

3 0

4 atoms

Explanation:

On the product side, we expect to find 4 atoms of the product.

An atom is the smallest indivisible particle that takes part in a chemical reaction.

An element is a distinct substance that cannot be split-up into simpler substances. Such substances consist of only one kind of atom.

In this reaction we have:

2 elements: Mg O

on the reactant side:

We have two moles of Mg: 2 atoms of Mg

1 mole of oxygen gas: 2 atoms of O

total atoms: 4 atoms

According to the law of conservation of matter "in a chemical reaction, matter is neither created nor destroyed".

We expect to find 4 atoms of products which is MgO on the product side.

2Mg + O₂ → 2MgO + heat

Learn more:

Conservation of matter brainly.com/question/2190120

#learnwithBrainly

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The rate constants for the reactions of atomic chlorine and of hydroxyl radical with ozone are given by 3 × 10-11 e-250/T and 2

Vlada [557]

Answer:

Calculate the ratio of the rates of ozone destruction by these catalysts at 20 km, given that at this altitude the average concentration of OH is about 100 times that of Cl and that the temperature is about -50 °C

Knowing

Rate constants for the reactions of atomic chlorine and of hydroxyl radical with ozone are given by 3x $10^{-11} e^{-255/T}$ and 2x $10^{-12} e^{-940/T}$

T = -50 °C = 223 K

The reaction rate will be given by [Cl] [O3] 3x $10^{-11} e^{-255/223} = 9.78^{-12} [Cl] [O3]$

Than, the reaction rate of OH with O3 is

Rate = [OH] [O3] 2x $10^{-12} e^{-940/223} = 2.95^{-14} [OH] [O3]$

Considering these 2 rates we can realize the ratio of the reaction with Cl to the reaction with OH is 330 * [Cl] / [OH]

Than, the concentration of OH is approximately 100 times of Cl, and the result will be that the reaction with Cl is 3.3 times faster than the reaction with OH

Calculate the rate constant for ozone destruction by chlorine under conditions in the Antarctic ozone hole, when the temperature is about -80 °C and the concentration of atomic chlorine increases by a factor of one hundred to about 4 × 105 molecules cm-3

Knowing

Rate constants for the reactions of atomic chlorine and of hydroxyl radical with ozone are given by 3x $10^{-11} e^{-255/T}$ and 2x $10^{-12} e^{-940/T}$

T = -80 °C = 193 K

The reaction rate will be given by [Cl] [O3] 3x $10^{-11} e^{-255/193} = 8.21^{-12} [Cl] [O3]$

Than, the reaction rate of OH with O3 is

Rate = [OH] [O3] 2x $10^{-12} e^{-940/193} = 1.53^{-14} [OH] [O3]$

Considering these 2 rates we can realize the ratio of the reaction with Cl to the reaction with OH is 535 * [Cl] / [OH]

Than, considering the concentration of Cl increases by a factor of 100 to about 4 × $10^{5}$ molecules $cm^{-3}$ , the result will be that the reaction with OH will be 535 + (100 to about 4 × $10^{5}$ molecules $cm^{-3}$ ) times faster than the reaction with Cl