On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 92.8 cm and diameter 2.05 cm from a storage room to a machinist, the weight of rod w is 23.41 N .
<h3>How is the weight calculated?</h3>
Given ,
density (d) = 7800 kg/m³
D = 2.05 cm = 0.0205 m
r = D/2 = 0.0205 / 2 =0.01025 m
h = 92.8 cm = 0.928 m
The weight is calculated by ,
W = m × g
But, to find mass (m)
m = d × V
The volume of the rod, because is cylindrical, is,
V = π × r² × h
∴ V = 3.14 × (0.01025)² × 0.928
∴ V = 3.14 × 1.051 × 10⁻⁴ × 0.928
∴ V = 3.0625 × 10⁻⁴
Now to calculate mass,
m = d × V
∴ m = 7800 × 3.0625 × 10⁻⁴
∴ m = 2.3887 Kg
Now, for calculating weight
W = m × g
∴ W = 2.3887 × 9.8
∴ W = 23.41 N
∴ The weight of the rod W assuming the free-fall acceleration is 23.41 N .
<h3>What is weight?</h3>
- The weight of an object is the force exerted on it by gravity.
- It is define weight as a vector quantity, the force of gravity acting on an object.
- Some define weight as a scalar quantity that is the magnitude of gravity.
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Answer:
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to the right the first answer on the top can be "Carnivore" under it can go "Herbivore" and under it can go "Producer"
I just had this question and its right
Answer:
AB = 29
Explanation:
For a better understanding, we must work this problem in a graphic way. In the attached image we can see the solution.
First, we draw a vertical dotted lines from the point J & K to the line ML, then we can see two new portions with the same length. Then with this simple analysis:
2x = 39 - 19
x = 10
Then we know that x = 10, another important data to find the answer is that the AB line is located in the midpoints of the legs. We also can see the right triangle MJ and the dotted line.
Now for every single right triangle, no matter its size and relationship between the vertical and the horizontal lengths, if some point is located in the hypotenuse (leg) at the middle of its length. This will be proportional to the vertical and the horizontal cathetus, therefore we will have the middle point on those two lines.
So, the AB line will be the sum of JK plus two times 5
AB = 19 + 5 + 5 = 29
Constant velocity means the netto force = 0, therefore F(gravity) = F(astronaut).
175N divided by 87,5kg = 2.00kg/N
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