A. through a relatively short distance.
The speed is actually called the drift speed of the electron.
Answer:
57,42 KJ
Explanation:
By a isobaric proces, the expresion for the works in the jpg adjunt. Then:
W = Pa(Vb - Va) = Pa*Vb - Pa*Va ---(1)
By the ideal gases law: PV=RTn
Then, in (1): (remember Pa = Pb)
W = R*Tb*n - R*T*an = R*n*(Tb - Ta) --- (2)
Since we have 1 Kg air: How much is this in moles?
From bibliography: 28.96 g/mol
Then, in 1 Kg (1000 g) there are:
n = 34,53 mol
Finally, in (2):
W = (8,3144 J/K.mol)*(34,53 mol)*(500K - 300K) = 51 419,9 J ≈ 57,42 KJ
Gamma ray<span> (also called </span>gamma radiation<span>), denoted by the lower-case Greek letter </span>gamma,<span> is penetrating </span>electromagnetic radiation<span> of a kind arising from the </span>radioactive decay<span> of </span>atomic nuclei<span>. It consists of </span>photons<span> in the highest observed range of </span>photon energy<span>. </span>