Answer:
A) pbin = 1.535 Kgm/s (+)
B) pbf = 1.696 Kgm/s (-)
C) Δp = 3.3925 Kgm/s
D) Δvr = 10.249 m/s
Explanation:
Given
Mass of the ball: m = 57.5 g = 0.0575 Kg
Initial speed of the ball: vbi = 26.7 m/s
Mass of the racket: M = 331 g = 0.331 Kg
Final speed of the ball: vbf = 29.5 m/s
A) We use the formula
pbin = m*vbi = 0.0575 Kg*26.7 m/s = 1.535 Kgm/s (+)
B) pbf = m*vbf = 0.0575 Kg*29.5 m/s = 1.696 Kgm/s (-)
C) We use the equation
Δp = pbf - pbin = 1.696 Kgm/s - (-1.535 Kgm/s) = 3.3925 Kgm/s
D) Knowing that
Δp = 3.3925 Kgm/s
we can say that
Δp = M*Δvr
⇒ Δvr = Δp / M
⇒ Δvr = 3.3925 Kgm/s / 0.331 Kg
⇒ Δvr = 10.249 m/s
Answer:
18.9 <em>N or </em><em>19</em><em> N </em>rounded
Explanation:
m = 0.145 kg
a = 130 m/s^2
F = ma = (0.145 kg)(130 m/s^2) = 18.9 <em>N</em>
Acceleration a=3m/s^2
time t= 4.1seconds
Final velocity V= 55km/h
initial velocity U= ?
First convert V to m/s
36km/h=10m/s
55km/h= 55*10/36=15.28m/s
Using the formula V= U+at
U= V-at
U= 15.28-3*4.1=15.28-12.3=2.98m/s
Initial velocity U= 2.98m/s or 10.73km/h (Using the conversion rate 36km/h=10m/s)
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