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solong [7]
3 years ago
9

At what speed does a 1800 kg compact car have the same kinetic energy as a 15000 kg truck going 21 km/h ? Express your answer in

kilometers per hour.
Physics
1 answer:
Digiron [165]3 years ago
8 0

Answer:

v = 60.62 km/h

Explanation:

Kinetic energy

Kinetic energy is that which is due to the movement of bodies and is calculted like this:

K = (1/2)mv² Formula (1)

Where:

K : Kinetic energy (J)

m: mass (kg)

v : speed (m/s)

Data for the truck

m = 15000 kg

v= 21 km/h = 21 *(1000m)/ (3600s)

v= 5.83 m/s

Calculation of the kinetic energy of the truck

We replace data in the formula (1)

K = (1/2)mv²

K = (1/2)(15000)(5.83)²

K = 255208.3 J

Data for the compact car

K = 255208.3 J =  255208.3 (N*m)

m = 1800 kg

Calculation of the speed  of the compact car

We replace data in the formula (1)

K = (1/2)mv²

255208.3 = (1/2)( 1800)(v)²

255208.3 = ( 900)(v)²

v² = 255208.3 / ( 900)

v= \sqrt{\frac{255208.3}{900} }

v = 16.84 m/s

1 km = 1000 m

1 h = 3600 s

v = 16.84*(3600/1000)km/h

v = 60.62 km/h

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the answer is 5 electrons

Explanation:

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3 years ago
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Could someone answer this?
Nadusha1986 [10]

Answer:

Here the circuit in which a 4Ω resistor resistor is connected in series and two 8Ω resistor resistors are connected in parallel. Also, ammeter and voltmeter connected in series and parallel circuit respectively.

Now,

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The 4Ω resistor is linked in series with the circuit.

so, P o w e r = I

two

R, here i is the current through the resistor resistor R

1 6 = I

two

∗ 4 Ω

i = 2A

Now 2A passes through parallel resistors of 8Ω resistance.

we know that, in parallel, the potential difference must be constant,

the current is divided into two parts, because the same resistance current in each resistance will be half. then the current through each resistor in parallel is

2 A

two

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= 1 A

So finally the current through the 4Ω resistor = 2 A

current through each 8Ω resistor = 1 A

Explanation:

I hope this answer has helped you

6 0
3 years ago
Which applied force will allow a 7.65 kg block of ice to begin sliding on a sheet of ice? The block of ice has a kinetic coeffic
Anni [7]

Answer:

force for start moving is 7.49 N

force for moving constant velocity 2.25 N

Explanation:

given data

mass = 7.65 kg

kinetic coefficient of friction = 0.030

static coefficient of friction = 0.10

solution

we get here first weight of block of ice that is

weight of block of ice = mass  ×  g

weight of block of ice = 7.65 × 9.8 = 74.97 N

so here Ff = Fa

so for force for start moving is

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Fa =  7.49 N

and

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Fa =  weight × kinetic coefficient of friction

Fa = 74.97 × 0.030

Fa = 2.25 N

7 0
3 years ago
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A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled
ad-work [718]

Answer:

shown below

Explanation:

2 x 10⁷ as a number is 20,000,000

20,000,000 - 10 = 19,999,990

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in km/s

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in m/s

19,999,990 / 3600 = ~5555.56 m/s

7 0
1 year ago
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