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4 years ago

Scienests use critical thinking skills throughout the process of research or experimentation. A student notices than

Chemistry

1 answer:

zhenek [66]4 years ago

4 0

Answer:go read ur book and u will find it!!

Explanation:

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Which statement is true about the cells of non-living objects? A. They have prokaryotic cells. B. They have eukaryotic cells. C.

zloy xaker [14]

D, obviously. All living things are made of one or more cells, therefore non-living things aren’t made of cells

8 0

3 years ago

3. Ethanol has a density of 0.800 g/mL. a. What is the mass of 225 mL of ethanol?

dedylja [7]

Since the ethanol has a density of 0.800 g/mL, the mass of the ethanol is 180 grams.

Given the following data:

Volume of ethanol = 225 mL

Density of lead ball = 0.800 g/mL.

To find the mass of the ethanol;

Density can be defined as mass all over the volume of an object.

Mathematically, the density of a substance is given by the formula;

$Density = \frac{Mass}{Volume}$

Making mass the subject of formula, we have;

$Mass = Density \times Volume$

Substituting the given parameters into the formula, we have;

Mass of ethanol = 180 grams.

3 0

3 years ago

What is the mass in kilograms of an object that weighs 50.0lbs?

Aleonysh [2.5K]

The amount of matter in an object is said to be its mass. The SI base unit of mass is kilograms i.e. $kg$ .

The mass of the object = $50.0 lbs$ (given)

For converting lbs to kg:

$1 lb = 0.453592 kg$

So, $50 lbs = 50\times 0.453592 kg = 22.6796 kg \simeq 22.68 kg$

Hence, the mass of $50.0lbs$ object in kilograms is $22.68 kg$ .

5 0

3 years ago

Pproximately how many particles are in 3 moles?

Fynjy0 [20]

Then why did you ask ??...........

................

3 0

3 years ago

Calculate the value of the diffusion coefficient D (in m2/s) at 547°C for the diffusion of some species in a metal; assume that

svetlana [45]

Answer : The value of diffusion coefficient is, $2.97\times 10^{-16}m^2/s$

Explanation :

Formula used :

$D=D_o\times \exp \left(-\frac{Q_d}{RT}\right )$

where,

D = diffusion coefficient = ?

$D_o$ = $5.6\times 10^{-5}m^2/s$

$Q_d$ = $177kJ/mol$

R = gas constant = 8.314 J/mol.K

T = temperature = $547^oC=273+547=820K$

Now put all the given values in the above formula, we get:

$D=5.6\times 10^{-5}m^2/s\times \exp \left(-\frac{177kJ/mol}{(8.314J/mol.K)\times (820K)}\right )$

$D=2.97\times 10^{-16}m^2/s$

Thus, the value of diffusion coefficient is, $2.97\times 10^{-16}m^2/s$

6 0

3 years ago