Answer:
62.36 g
Explanation:
AgNO3 + H2SO4 - > Ag2SO4 + HNO3
The balanced equation is given as;
2AgNO3 + H2SO4 → Ag2SO4 + 2HNO3
From the equation;
2 mol of AgNO3 reacts with 1 mol of H2SO4
if 0.200 moles of AgNO3 react with 0.155 moles of H2SO4
The limiting reactant us AgNO3 as it determines the amount of products to be formed.
2 mol of AgNO3 produces 1 mol of Ag2SO4
0.2 mol of AgNO3 would produce x mol of Ag2SO4
Solving for x;
2 = 2
0.2 = x
x =0.2 * 2/ 2 = 0.2 mol
Converting moles to mass;
Mass = Number of Moles * Molar mass
Mass = 0.2 mol * 311.8 g/mol
Mass = 62.36 g
