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bixtya [17]
3 years ago
7

if 0.200 moles of AgNO3 react with 0.155 moles of H2SO4 according to this UNBALANCED equation below, how many grams of AgSO4 cou

ld be formed? AgNO3+H2SO4->Ag2SO4+HNO3
Chemistry
1 answer:
sladkih [1.3K]3 years ago
7 0

Answer:

62.36 g

Explanation:

AgNO3 + H2SO4 - > Ag2SO4   + HNO3

The balanced equation is given as;

2AgNO3 + H2SO4 → Ag2SO4 + 2HNO3  

From the equation;

2 mol of AgNO3 reacts with 1 mol of H2SO4

if 0.200 moles of AgNO3 react with 0.155 moles of H2SO4

The limiting reactant us AgNO3 as it determines the amount of products to be formed.

2 mol of AgNO3 produces 1 mol of Ag2SO4

0.2 mol of AgNO3 would produce x mol of Ag2SO4

Solving for x;

2 = 2

0.2 = x

x =0.2 * 2/ 2 = 0.2 mol

Converting moles to mass;

Mass = Number of Moles * Molar mass

Mass = 0.2 mol * 311.8 g/mol

Mass = 62.36 g

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Sergeu [11.5K]

Answer:

23.0 s⁻¹ is rate constant

Explanation:

Using the Arrhenius equation:

k = A * e^(-Ea/RT)

Where k is rate constant

A is frequency factor (1.5x10¹¹s⁻¹)

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And T is absolute temperature (24°C + 273 = 297K)

Replacing:

k = 1.5x10¹¹s⁻¹ * e^(-55800J/mol/8.314J/molK*297K)

k = 1.5x10¹¹s⁻¹ * 1.53x10⁻¹⁰

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Explanation:

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3 years ago
The first step in HNO3 production is the catalyzed oxidation of NH3. Without a catalyst, a different reaction predominates:
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Answer:

Kc = 6x10⁻⁶

Explanation:

For the reaction:

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Kc is defined as:

Kc =[N₂]² [H₂O]⁶ / [NH₃]⁴ [O₂]³

The equilibrium concentrations of the gases is -Because volume of the container is 1.00L-:

[N₂] = 2X = 1.96x10⁻³; <em>X = 9.8x10⁻⁴</em>

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Replacing in Kc expression:

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3 years ago
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Answer:

<h2>0.44 </h2>

Explanation:

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From the question we have

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