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bixtya [17]
3 years ago
7

if 0.200 moles of AgNO3 react with 0.155 moles of H2SO4 according to this UNBALANCED equation below, how many grams of AgSO4 cou

ld be formed? AgNO3+H2SO4->Ag2SO4+HNO3
Chemistry
1 answer:
sladkih [1.3K]3 years ago
7 0

Answer:

62.36 g

Explanation:

AgNO3 + H2SO4 - > Ag2SO4   + HNO3

The balanced equation is given as;

2AgNO3 + H2SO4 → Ag2SO4 + 2HNO3  

From the equation;

2 mol of AgNO3 reacts with 1 mol of H2SO4

if 0.200 moles of AgNO3 react with 0.155 moles of H2SO4

The limiting reactant us AgNO3 as it determines the amount of products to be formed.

2 mol of AgNO3 produces 1 mol of Ag2SO4

0.2 mol of AgNO3 would produce x mol of Ag2SO4

Solving for x;

2 = 2

0.2 = x

x =0.2 * 2/ 2 = 0.2 mol

Converting moles to mass;

Mass = Number of Moles * Molar mass

Mass = 0.2 mol * 311.8 g/mol

Mass = 62.36 g

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Answer:

Radio waves

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3 years ago
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Answer:

The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³

Explanation:

Step 1: Data given

For the reaction aA + bB ⇆ cC + dD

the equilibrium constant Kc = [C]^c * [D]^d/[B]^b*[A]^a

Step 2: The balanced equation

Fe2O3(s) + 3H2(g) --> 2Fe(s) + 3H2O(g)

Step 3: Calculate the equilibrium constant Kc

Kc =  [C]^c * [D]^d/[B]^b*[A]^a

⇒with [C] = [Fe]

⇒ with c = 2

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⇒with a = 1

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⇒with b = 3

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The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³

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A student mixes a 10.0 ml sample of 1.0 m naoh(aq) with a 10.0 ml sample of 1.0 m hcl(aq) in a polystyrene container. the temper
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