How much heat has been lost when a 78 g piece of copper is placed into a calorimeter and cools from 120°C to

Chemistry

1 answer:

lora16 [44]2 years ago

3 0

The amount of heat lost by the copper is 2402.4 J.

To Calculate the amount of heat lost, we use the formula below.

<h3>Formula:</h3>

Q = cm(t₂-t₁)................. Equation 1

<h3>Where:</h3>

Q = Amount of heat lost
c = specific heat capacity of copper
m = mass of copper
t₂ = Final temperature
t₁ = Initial temperature

From the question,

<h3>Given:</h3>

m = 78 g
c = 0.385 J/g°C
t₂ = 120°C
t₁ = 40°C

Substitute these values into equation 1.

Q = 78(0.385)(120-40)
Q = 2402.4 J

Hence, The heat lost by the copper is 2402.4 J

Learn more about heat here: brainly.com/question/13439286

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Calculate the mass of chloroform that contains 1.00X10^12 molecules of chloroform

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<span>Molar mass of chloroform (CHCl3)
C = 1 * 12 = 12 a.m.u
H = 1 * 1 = 1 a.m.u
Cl = 3 * 35.5 = 106.5 a.m.u
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x → $6,02 * 10^{35}$

$6,02 * 10 ^ {23} * x = 119,5 * 6,02 * 10 ^{35}$
$6,02 * 10 ^ {23}x = 719,39 * 10^{35}$
$x = \frac{719,39}{6,02}*10^{35-23}$
$\boxed{x = 119,5*10^{12}grams}$

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