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zmey [24]
2 years ago
14

How much heat has been lost when a 78 g piece of copper is placed into a calorimeter and cools from 120°C to

Chemistry
1 answer:
lora16 [44]2 years ago
3 0

The amount of heat lost by the copper is 2402.4 J.

To Calculate the amount of heat lost, we use the formula below.

<h3>Formula:</h3>
  • Q = cm(t₂-t₁)................. Equation 1

<h3>Where:</h3>
  • Q = Amount of heat lost
  • c = specific heat capacity of copper
  • m = mass of copper
  • t₂ = Final temperature
  • t₁ = Initial temperature

From the question,

<h3>Given:</h3>
  • m = 78 g
  • c = 0.385 J/g°C
  • t₂ = 120°C
  • t₁ = 40°C

Substitute these values into equation 1.

  • Q = 78(0.385)(120-40)
  • Q = 2402.4 J

Hence, The heat lost by the copper is 2402.4 J

Learn more about heat here: brainly.com/question/13439286

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4 b + 3 o2 → 2 b2o3 if 8 moles of b and 4 moles of o2 are allowed to react, how many moles of b2o3 can be formed?
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<h3>Limiting reagent</h3>

The limiting reagent is the reactant that will be completely used up.

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from the equation above;

4 b ------------> 2 b₂O₃

2b ------------> b₂O₃

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3  :  2

b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;

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