All categories

2 years ago

How much heat has been lost when a 78 g piece of copper is placed into a calorimeter and cools from 120°C to

Chemistry

1 answer:

lora16 [44]2 years ago

3 0

The amount of heat lost by the copper is 2402.4 J.

To Calculate the amount of heat lost, we use the formula below.

<h3>Formula:</h3>

Q = cm(t₂-t₁)................. Equation 1

<h3>Where:</h3>

Q = Amount of heat lost
c = specific heat capacity of copper
m = mass of copper
t₂ = Final temperature
t₁ = Initial temperature

From the question,

<h3>Given:</h3>

m = 78 g
c = 0.385 J/g°C
t₂ = 120°C
t₁ = 40°C

Substitute these values into equation 1.

Q = 78(0.385)(120-40)
Q = 2402.4 J

Hence, The heat lost by the copper is 2402.4 J

Learn more about heat here: brainly.com/question/13439286

You might be interested in

Which of the following is the poorest conductor electricity

mojhsa [17]

Answer:

Fluorine

Explanation:

It is a non-metal does not conduct electricity

5 0

2 years ago

Elements - made up of<br> Ex:

astra-53 [7]

All elements are made up of atoms. ➢ Atoms are made up of protons, neutrons, and electrons. Two different kinds of atoms can combine to form a compound. A molecule is a combination of atoms that cannot be broken apart while still retaining the same properties as the larger substance that it is a part of.

7 0

3 years ago

The thallium Subscript 81 Superscript 208 Baseline Tl nucleus is radioactive, with a half-life of 3.053 min. At a given instant,

Genrish500 [490]

Answer: (E) 300 bq

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations. The radioactive decay follows first order kinetics.

Half life is represented by $t_{\frac{1}{2}$

Half life of Thallium-208 = 3.053 min

Thus after 9 minutes , three half lives will be passed, after ist half life, the activity would be reduced to half of original i.e. $\frac{2400}{2}=1200$ , after second half life, the activity would be reduced to half of 1200 i.e. $\frac{1200}{2}=600$ , and after third half life, the activity would be reduced to half of 600 i.e. $\frac{600}{2}=300$ ,

Thus the activity 9 minutes later is 300 bq.

7 0

2 years ago

If the titrant has a molarity of 0.1000 m and there are 45.00 ml of analyte present, what is the molarity of the analyte?

marysya [2.9K]

Given:

Concentration of titrant = 0.1000 M
Volume of titrant = 45 mL

The molarity of analyte depends on the amount of the analyte present in the titrated solution. If the amount of analyte is 20 mL, then its concentration is:

45ml * 0.10 M = C analyte * 20 ml

C analyte = 0.225 M

4 0

2 years ago

How many atoms of each element are in the chemical formula P2O5?

marshall27 [118]

Answer:A

Explanation:2 phosphorus and 2 oxygen

4 0

3 years ago