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3 years ago

Number 41? Need help how do you get answrb

Chemistry

1 answer:

Wittaler [7]3 years ago

3 0

To find the formulae, you must add as many of the ions together to get a neutral charge. For example, one Li^+ ion and one NO2^- ion give LiNO2, which is lithium nitrite, but since CO3^2- has a charge of -2, it needs 2 Li^+ ions to make the neutral compound Li2CO3, lithium carbonate. Similarly, Cu^2+ needs 2 NO2^- ions to make the neutral compound Cu(NO2)2, copper(II) nitrite. To name these, simply add together the names of the ions used. Li^+ is lithium, Cu^2+ is copper(II), and Ba^2+ is barium. The negatively charged ions are named as nitrite for NO2^-, carbonate for CO3^2-, bisulfate for HSO4^- and phosphate for PO4^3-.

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In acidic solution, the nitrate ion can be used to react with a number of metal ions. One such reaction is NO3−(aq)+Sn2+(aq)→NO2

katrin [286]

Answer:

$\boxed{\text{2, 1, 4, 2, 1, 2}}$

Explanation:

NO₃⁻ + Sn²⁺ + __ → NO₂ + Sn⁴⁺ + __

Step 1: Separate into two half-reactions.

NO₃⁻ ⟶ NO₂

Sn²⁺ ⟶ Sn⁴⁺

Step 2: Balance all atoms other than H and O.

Done

Step 3: Balance O.

NO₃⁻ ⟶ NO₂ + H₂O

Sn²⁺ ⟶ Sn⁴⁺

Step 4: Balance H

NO₃⁻ + 2H⁺ ⟶ NO₂ + H₂O

Sn²⁺ ⟶ Sn⁴⁺

Step 5: Balance charge.

NO₃⁻ + 2H⁺ + e⁻ ⟶ NO₂ + H₂O

Sn²⁺ ⟶ Sn⁴⁺ + 2e⁻

Step 6: Equalize electrons transferred.

2 × [NO₃⁻ + 2H⁺ + e⁻ ⟶ NO₂ + H₂O]

1 × [Sn²⁺ ⟶ Sn⁴⁺ + 2e⁻]

Step 7: Add the two half-reactions.

2 × [NO₃⁻ + 2H⁺ + e⁻ ⟶ NO₂ + H₂O]

2NO₃⁻ + Sn²⁺ + 4H⁺ ⟶ 2NO₂ + Sn⁴⁺ + 2H₂O

Step 8: Check mass balance.

On the left: 2 N, 6 O, 1 Sn, 4H

On the right: 2 N, 6 O, 1 Sn, 4H

Step 9: Check charge balance.

On the left: -2 + 6 = +4

On the right: +4

The equation is balanced.

$\text{The coefficients are }\boxed{\textbf{2, 1, 4, 2, 1, 2}}$

4 0

3 years ago

All alkali earth metals have the same reactivity with water. True or False

zheka24 [161]

True. Water is a neutral substance so nothing should react to it, this makes it so that no matter how basic a metal is, it reacts the same to water.

4 0

3 years ago

A 16.9 gram sample of KCl is used to mak a 250 mL KCl solution. What is the molarity of the KCl solution?

Genrish500 [490]

Answer:

0.906 gm/l

Explanation:

We know that molarity of the a solution is given by,

$M= \frac{w}{m} \times \frac{1000}{v}$ , where 'M' is the molarity, 'w' is the weight of the sample, 'm' is the molar mass, and 'v' is the volume of the solution.

Molarity of a solution tells us the concentration of the solute in the solvent.

Molar mass of KCl is = 74.55

Putting the values we get,

$M = \frac{16.9}{74.55} \times \frac{1000}{250}=0.906 gm/l$

So the molarity of KCl solution is 0.906 gm/l.

5 0

2 years ago

Read 2 more answers

Why are(±)-glucose and (-)-glucose both classified as D sugar

vazorg [7]

Answer:

See explanation

Explanation:

We must remember that the D / L nomenclature refers to the orientation of the hydroxyl group on carbon 5. If the "OH" is on the right we will have a D configuration. Yes, the "OH" is on the left we will have an L configuration. (See figure 1)

Now, the orientation of this "OH" has nothing to do with the ability of the molecule to deflect polarized light. If the molecule deflects light to the left we will have the symbol "(-)" (levorotation) if the molecule deflects light to the right we will have the symbol "(+)" (dextrorotation).

So in the "D" configuration, we can have both a right (+) and a left (-) deviation.

I hope it helps!

7 0

3 years ago

Type the correct answer in the box.

muminat

Answer: 6 valence electrons

Explanation: the valence electrons and group are always the same, but when the group numbers are 10 and above, they would be the first number. For example, every element in group 16 has 6 valence electrons.

4 0

3 years ago