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Fudgin [204]
3 years ago
6

A 450 MWt combined cycle plant has a Brayton cycle efficiency of 24% and a Rankine cycle efficiency of 29% with no heat augmenta

tion. Determine the net electric output from the plant.
Engineering
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

Output of plant=207.18 MW

Explanation:

Given input energy Q=450 MW

Brayton cycle efficiency\eta_1=24%

Rankine cycle efficiency \eta_2=29%

Combined efficiency for two cycle given as follow

\eta _b=\eta _1+\eta _2-\eta _1\eta _2

\eta _b=0.24+0.29-0.24\times 0.29

\eta_b=0.4604

We know that efficiency \eta =\dfrac{out\ put}{in\ put}

out put of plant=450\times 0.4604

So output of plant=207.18 MW

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Consider a cubic block whose sides are 6 cm long and a cylindrical block whose height and diameter are also 6 cm. both blocks ar
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3 years ago
The water in a 25-m-deep reservoir is kept inside by a 140-m-wide wall whose cross section is an equilateral triangle as shown i
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The average pressure on the surface of the wall is the pressure at the centeroid of the equilateral triangular block which can be then be calculated by multiplying it with the Plate Area which will provide us with the Resultant force.

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Po/\rho g sin60 = 100000/1000 * 9.81* sin(60) = 11.77 m \\ \\

From the second image attached the distance of the pressure center from the free surface of the water along the surface of the wall is given by:

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So they can grasp a better understanding! good luck
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