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Fudgin [204]
3 years ago
6

A 450 MWt combined cycle plant has a Brayton cycle efficiency of 24% and a Rankine cycle efficiency of 29% with no heat augmenta

tion. Determine the net electric output from the plant.
Engineering
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

Output of plant=207.18 MW

Explanation:

Given input energy Q=450 MW

Brayton cycle efficiency\eta_1=24%

Rankine cycle efficiency \eta_2=29%

Combined efficiency for two cycle given as follow

\eta _b=\eta _1+\eta _2-\eta _1\eta _2

\eta _b=0.24+0.29-0.24\times 0.29

\eta_b=0.4604

We know that efficiency \eta =\dfrac{out\ put}{in\ put}

out put of plant=450\times 0.4604

So output of plant=207.18 MW

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