Why does my delivery date keep changing on my tesla model 3

A solid round bar with a diameter of 2.32 in has a groove cut to a diameter of 2.09 in, with a radius of 0.117 in. The bar is no

Alenkinab [10]

Answer:

nf=1.11 (Goodman criterion)

ny=2.41 (factor of safety for fatigue)

Explanation:

From the table A-20 Deterministic ASTM minimum tensile and yield strengths for HR and CD steels, we have approximately:

Sut=120 kpsi

Sy=66 kpsi

Due Sut<1400 Mpa, the endurance limit is:

$Se=0.5Sut=0.5*120=60 kpsi$

The surface condition modification factor is:

$ka=a(Sut)^{b}=2.7(120)^{-0.265} =0.759$

The effective diameter is:

$de=0.37d=0.37*2.09=0.7733 in$

The size factor is:

$kb=0.879de^{-0.107} =0.879(0.7733)^{-0.107} =0.9$

The endurance limit at critical location is:

$See=ka*kb*kc*kd*kd*ke*kf*Se=0.759*0.9*1*60=40.986 kpsi$

$\frac{D}{d}=\frac{2.32}{2.09} =1.11\\\frac{r}{d}=\frac{0.117}{2.09} =0.056$

From Figure A-15-15 chart, the Kf = 2.1

The notch sensitivity is:

$\sqrt{a}=0.246-3.08(10^{-3})Sut+1.51(10^{-5})Sut^{2}-2.67(10^{-8})Sut^{3}$

$\sqrt{a}=0.246-3.08(10^{-3})(120)+1.51(10^{-5})(120^{2})-2.67(10^{-8})(120^{3})=0.048$

$q=\frac{1}{1+\frac{\sqrt{a} }{\sqrt{r} } }=\frac{1}{1+\frac{0.048}{\sqrt{0.117} } }=0.877$

The fatigue stress is:

$Kf=1+q(Kt-1)=1+0.877(2.1-1)=1.96$

The moment of inertia is:

$I=\frac{\pi }{64} d^{4}=\frac{\pi }{64} (2.09^{4})=0.936 in^{4}$

The maximum stress is:

$omax=\frac{M*c}{I}=\frac{25000*\frac{2.09}{2} }{0.936} =27911.32 psi=27.911 kpsi$

The mean stress is:

$om=Kf\frac{omax+omin}{2} =1.96\frac{27.911+0}{2}=27.35 kpsi$

The alternate stress is:

$oa=Kf|\frac{omax-omin}{2}|=27.35 kpsi$

The fatigue factor using Goodman is:

$\frac{1}{nf}=\frac{oa}{See}+\frac{om}{Sut}\\\frac{1}{nf}=\frac{27.35}{40.986}+\frac{27.35}{120}$

nf=1.11

the factor of safety is:

$ny=\frac{Sy}{omax}=\frac{66}{27.35} =2.41$

4 0

4 years ago

When lining up the song on the tempo grid it is important to allow

Reika [66]

Tempo decides the speed at which the music is played.

<u>Explanation:</u>

The Tempo of a bit of music decides the speed at which it is played, and is estimated in beats per minute (BPM). The 'beat' is dictated when mark of the piece, so 100 BPM in 4/4 compares to 100 quarter notes in a single moment.

A quick tempo, prestissimo, has somewhere in the range of 200 and 208 beats for each moment, presto has 168 to 200 beats for every moment, allegro has somewhere in the range of 120 and 168 beats for every moment, moderato has 108 to 120 beats for every moment, moderately slow and even has 76 to 108, adagio has 66 to 76, larghetto has 60 to 66, and largo, the slowest rhythm, has 40 to 60.

6 0

3 years ago

A balanced three phase load is supplied over a three-phase , 60 hz, transmission line with each line have a series impedance of

posledela

Answer:

Explanation:

Given a three-phase system

Frequency f=60Hz

Line impedance Z= 12.84 + j72.76 Ω

Then,

The resistance is R=12.84Ω

And reactance is X=72.76Ω

Z=√(12.84²+72.76²)

Z=73.88

Angle = arctan(X/R)

Angle = arctan(72.76/12.84)

Angle=80°

Then, Z=73.88 < 80° ohms

Load voltage is 132 kV

Load power P=55 MWA

Power factor =0.8lagging

the relation between the sending and receiving end specifications are given using ABCD parameters by the equations below.

Vs = AVr + BIr

Is = CVr + DIr

Where

Vs is sending Voltage

Vr is receiving Voltage

Is is sending current

Ir is receiving current

A is ratio of source voltage to received voltage A=Vs/Vr when Ir=0

B is short circuit resistance

B= Vs/Ir when Vr=0

C is ratio of source current to received voltage C=Is/Vr when Ir=0

D is ratio of source current to received current D=Is/Ir when Vr=0

Now,

The load at 55MVA at 132kV (line to line)

Therefore, load current is

Ir= P/V√3

Ir=55×10^6/(132×10^3×√3)

Ir=240.56 Amps

It has a power factor 0.8 lagging

PF=Cosθ

0.8=Cosθ

θ=arcCos(0.8)

θ=36.87°

Therefore, Ir=240.56 <-36.87°

Vr=V/√3

Vr=132/√3

Vr=76.21 kV. Phase voltage

Vr= 76210 < 0° V

For series impedance,

Using short line approximation

Vs = Vr + IrZ

Vs = 76210 < 0° + (240.56 <-36.87° × 73.88 < 80°)

Using calculator

Vs=76210<0° + 17772.5728<(-36.87°+80°)

Vs=76210<0° + 17772.5728<43.13°

Vs=89970.67<7.7°

Also

Is = Ir = 240.56 <-36.87° Amps

Therefore, the ABCD parameters is

A=Vs/Vr

A= 89970.67 <7.7° / 76210 <0°

A=1.181 <7.7-0

A=1.18 <7.7° no unit

B = Vs/Ir

B = 89970.67 < 7.7° / 240.56 <-36.87°

B = 347.01 < 7.7+36.87

B= 347.01 < 44.57° Ω

C= Is/Vr = 240.56 <-36.87° / 76210 < 0°

C= 0.003157 <-36.87-0

C= 3.157 ×10^-3 < -36.87° /Ω

C= 3.157 ×10^-3 < -36.87° Ω~¹

D= Is/Ir

Since Is=Ir

Then, D = 1 no unit.

8 0

3 years ago

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AVprozaik [17]

Explanation:

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8 0

2 years ago

Read 2 more answers

What is clearance? What is backlash? What is interference? Explain briefly.

Anton [14]

Explanation:

Clearance:

For easy matching and dis matching of hole and shaft we use size of hole little bit more than the size of shaft and this difference in size is called clearance.

Backlash:

It is the clearance between the two mating gear to avoids failure of gears.Actually when temperature of gears increases then at the same time the size of gear also increases ,due this there is a possibility foe jamming of gears so to avoids this backlash is provides.

Interference:

When two gears are matting then addendum of one gear inters into the deddendum of another gear and due to this gears get jam .This phenomenon is called interference.

5 0

3 years ago