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ANEK [815]
3 years ago
11

The products of combustion from a burner are routed to an industrial application through a thin-walled metallic duct of diameter

Di=1 m and length L=100 m. The gas enters the duct at atmospheric pressure and a mean temperature and velocity of Tm,i=1600 K and Um,i=10 m/s, respectively. It must exit the duct at a temperature that is no less than Tm,o=1400 K. What is the minimum thickness of an alumina-silica insulation (Kins=0.125 W/m*K) needed to meet the outlet requirement under worst case conditions for which the duct is exposed to ambient air at T[infinity]=250 K and a cross-flow velocity of V=15 m/s? The properties of the gas may be approximated as those of air, and as a first estimate, the effect of the insulation thickness on the convection coefficient and the thermal resistance associated with the cross flow may be neglected.

Engineering
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

0.11m

Explanation:

Thermal resistance can be rightly defined as a heat property and a measurement of a temperature difference by which an object or material resists a heat flow.

Please for the detailed step by step solution of the given problem, check the attached file.

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Answer:

V1=5<u>ft3</u>

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Explanation:

PART A:

the volume of each state is obtained by multiplying the mass by the specific volume in each state

V=volume

v=especific volume

m=mass

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state 1

V1=m.v1

V1=4lb*1.25ft3/lb=5<u>ft3</u>

state 2

V2=m.v2

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PART B:

since the PV ^ n is constant we can equal the equations of state 1 and state 2

P1V1^n=P2V2^n

P1/P2=(V2/V1)^n

ln(P1/P2)=n . ln (V2/V1)

n=ln(P1/P2)/ ln (V2/V1)

n=ln(15/53)/ ln (2/5)

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Answer:

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Answer:

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Read 2 more answers
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