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3 years ago

What is 100 kPa in psia?

Engineering

1 answer:

Korolek [52]3 years ago

8 0

Answer:

The pressure in pounds per square inch (psi) equals 14.50 psi.

Explanation:

Since psi stands for 'pounds per square inch' and Pascals stands for 'Newtons per square meters'

We can write the given pressure as

$Pressure=100kPa\\\\Pressure=100\times 10^{3}N/m^{2}$

Now since 1 Newton of force equals 0.22481 Pound force also

since 1 meter equals 39.37 inches

Using the above values we get

$Pressure=100\times 10^{3}\times \frac{0.22481lb}{(39.37)^{2}inch^{2}}$

thus the pressure becomes

$Pressure=100\times 10^{3}\times \frac{0.22481}{(39.31)^{2}}pounds/inch^{2}\\\\Pressure=14.50psi$

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harina [27]

Answer:

Power = 371.28 kW

Explanation:

Initial pressure, P1 = 5 bar

Final pressure, P2 = 1 bar

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Final temperature, T2 = 160°C

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From steam tables at state 1,

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v1 = 0.5416 m³/kg

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From steam tables, at state 2

h2 = 2796.2 kJ/kg, s2 = 7.6597 kJ/kgK

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3 years ago

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3 years ago

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Given a mass-spring-damper system. The impulse response of strength 1 can be obtained from a unit step response by: ______

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Answer:

Multiplying impulse response by t ( option D )

Explanation:

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2 years ago

For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of t

saveliy_v [14]

Complete Question

For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 411 MPa (59610 psi) is applied if the original length is 470 mm (18.50 in.)?Assume a value of 0.22 for the strain-hardening exponent, n.

Answer:

The elongation is $=21.29mm$

Explanation:

In order to gain a good understanding of this solution let define some terms

True Stress

A true stress can be defined as the quotient obtained when instantaneous applied load is divided by instantaneous cross-sectional area of a material it can be denoted as $\sigma_T$ .

True Strain

A true strain can be defined as the value obtained when the natural logarithm quotient of instantaneous gauge length divided by original gauge length of a material is being bend out of shape by a uni-axial force. it can be denoted as $\epsilon_T$ .