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Liula [17]
3 years ago
14

Suppose that a car traveling to the west (the - x direction) begins to slow down as it approaches a traffic light. Which stateme

nt concerning its acceleration in the x direction is correct? (A) It's acceleration is negative but it's velocity is positive (B) It's acceleration is positive, but ti's velocity is negative. (C) Both its acceleration and its velocity are positive.
Physics
1 answer:
Amanda [17]3 years ago
4 0

Answer:

(A) it's acceleration is negative but but it's velocity is positive

Explanation:

In the question it is given that begins to slow down so its speed is decreasing it is does not means that its speed is negative

For example let first the velocity of the car is 30 m/sec and when its velocity decreases it becomes 20 m/sec in 5 sec

So it is not negative at all

Now the acceleration is the rate of change of velocity

a=\frac{dv}{dt}

a=\frac{v_2-v_1}{dt}=\frac{20-30}{5}=-2 m/sec^2

So acceleration is negative here

So option (a) will be the correct option

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The velocity of a particle (m = 10 mg, q = –4.0 μC) at t = 0 is 20 m/s in the positive x direction. If the particle moves in a u
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Answer:

Vf = - 20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction).

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Vi = 20 m/s, m= 10 mg =1 × 10⁻⁵ kg, q= -4.0 × 10⁻⁶ C , E= 20 N/C. t= 5.0 s

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F= Eq = 20 × -4.0 10⁻⁶ C = - 8 × 10⁻⁵ N (-ve sign shows that the field will push the particle opposite to positive x- direction)

We also have F=ma

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