Answer:
d it increase the number of collisions
Explanation:
cos collision is a type reaction to other particles
Hope that helps you
Please follow
What do u need help with? I’m sure I can help you
A chemical equation has 2 sides: the reactives side and the products side
For a chemical equation to be balanced these two side must have the same number of atoms of each type, since in a chemical reaction mass must stay the same
Each symbol in either side will have a subscript. A subscript is the tiny number at the bottom of the symbol. If a symbol has no subscript then that indicate there’s only one atom of that type. However if it has, for example, a 4, then that indicates the are 4 atoms of that type. The thing is these subscripts cannot be changed...
Ex.
HgO —> Hg + O₂
Hg = 1 Hg = 1
O = 1 O = 2
This is an unbalanced equation because the is not oxigen on side that the other.
To balance it u must add a coefficient. This number goes before the whole group of symbols — You can not break apart a group to insert a coefficient in the middle. This number is multiplied by the subscript on each of the symbols in the group. You need to find the correct coefficient to multiply by the elements on both sides of the equation.
Note that this coefficient does no have to be the same on both sides
Answer:
2HgO —> 2Hg + O₂
Hg = 2 Hg = 2
O = 2 O = 2
Explanation:
To fix the oxigen we need to add a coefficient to the side that has less quantity. Because 2 x 1 = 2 (1 Is oxigen’s subscript) we place the 2 in front of the group HgO, But in doing so we damage the mercury, so we need to go to the other side to fix that so we place 2 in front of Hg.
If you need any more help, have some exercises I can further explain or have more doubt about this explanation then let me know and I will help you
Ps: I do recommend you first write the quantity of each atom for each side like I did. It makes it easier to visualize what you have to balance
Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.
Commonly, sacrificial electrodes are employed to stop another metal from corroding or oxidising. A metal that is more reactive than the metal being shielded must serve as the sacrificial electrode. Magnesium, aluminium, and zinc are the three metals most frequently used in sacrificial anodes.
Manganese-Magnesium (Mn-Mg) electrode is more suited for on-shore pipelines where the electrolyte (soil or water) resistivity is higher since it has the highest negative electropotential of the three. In order to replenish any electrons that could have been lost during the oxidation of the shielded metal, the highly active metal offers its electrons.
Therefore, Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.
Learn more about electrode here:
brainly.com/question/17060277
#SPJ4
Water is a polar molecule because of its shape