The OH peaks in the IR spectra of benzyl alcohol and benzoic acid should be compared and contrasted.
<h3>What is the IR spectra of Benzoic acid?</h3>
- The right-hand portion of the infrared spectrum of benzoic acid, between wavenumbers 1500 and 400 cm-1, is referred to as the fingerprint region.
- It results from a special combination of intricately overlapping vibrations of the atoms within the benzoic acid molecule.
<h3>What is the IR spectra of Benzyl alcohol?</h3>
- A C-Cl bond is frequently shown by a peak at 700.
- There are a few more peaks at 1500 that are directed at a C=C bond.
<h3>What is IR spectra?</h3>
The percent transmittance (or absorbance) of the radiation through the molecule against the radiation's wave number forms the IR spectrum.
Learn more about IR spectra here:
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Answer: is neither an acid nor a base
Explanation: Water is a universal solvent which means it can dissolve most of the substances in it.
Water has high thermal heat capacity , which means large heat is required to heat the water.
Water is not always pure as it gets contaminated by various pollutants present in the atmosphere such as gases, bacteria and suspended matter.
Water is an amphoteric substance which can act as both acid and base, thus can donate and acept [texH^+[/tex] ions.Thus it is neither an acid nor a base.
Here water is accepting a proton, thus it acts as base.
Here water is donating a proton, thus it acts as acid.
Answer:
0.68 V
Explanation:
For anode;
3Mg(s) ---->3Mg^2+(aq) + 6e
For cathode;
2Al^3+(aq) + 6e -----> 2Al(s)
Overall balanced reaction equation;
3Mg(s) + 2Al^3+(aq) ----> 3Mg^2+(aq) + 2Al(s)
Since
E°anode = -2.356 V
E°cathode = -1.676 V
E°cell=-1.676 -(-2.356)
E°cell= 0.68 V
Answer:
0.85 Molar Na2O
Explanation:
Determine the moles of sodium oxide, Na2O, in 10 grams by dividing by the molar mass of Na2O (61.98 g/mole).
(10 g Na2O)/(61.98 g/mole) = 0.161 moles Na2O.
Molar is a measure of concentration. It is defined as moles/liter. A 1 M solution contains 1 mole of solute per liter of solvent. [200 ml water = 0.2 Liters water.]
In this case, we have 0.161 moles Na2O in 0.200 L of solvent.
(0.161 moles Na2O)/(0.200 L) = 0.85 Molar Na2O
