Answer:
I'd say the answer is Clustered (Based on the image)
Answer:
Tripling the concentration of A will triple the reaction rate.
Explanation:
- For a first–order reaction hat has a rate law:
<em>Rate = k[A].</em>
- It is clear that the reaction rate is directly proportional to the concentration of A.
<em>Rate ∝ [A].</em>
<u><em>So, Tripling the concentration of A will triple the reaction rate.</em></u>
Answer:
Ni (s) is oxidized because it loses electrons. This makes it the reducing agent.
CuCl₂ (aq) is reduced because it gains electrons. This makes it the oxidizing agent.
Explanation:
In the reaction:
Ni(s) + CuCl₂(aq) → Cu(s) + NiCl₂(aq)
Ni (s) is oxidized because it loses electrons. This makes it the reducing agent.
------------> Ni (s) has an oxidation number of 0. All lone atoms (that are not ions) have a 0 oxidation number.
-------------> In NiCl₂ (aq), chlorine must have an oxidation number of -1, and because there are two chorine atoms, they contribute a total -2 charge. To make the overall charge neutral, nickel must have an oxidation number of +2 to balance the charges.
--------------> Because nickel goes from an oxidation number of 0 to +2, this indicates that it lost electrons and was reduced.
CuCl₂ (aq) is reduced because it gains electrons. This makes it the oxidizing agent.
-------------> In CuCl₂ (aq), chlorine must have an oxidation number of -1, and because there are two chorine atoms, they contribute a total -2 charge. To make the overall charge neutral, copper must have an oxidation number of +2 to balance the charges.
------------> Cu (s) has an oxidation number of 0. All lone atoms (that are not ions) have a 0 oxidation number.
--------------> Because copper goes from an oxidation number of +2 to 0, this indicates that it gained electrons and was oxidized.
Answer:
choice 3
Explanation:
Hydrogen bonding occurs when a H is bonded to a highly electronegative atom like F. Towards the upper right corner, most atoms have high electronegativity and small atomic radii, according to periodic trends.
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For the answer to the question above, well presumably because the exact concentration of the composition KMnO4 solution doesn't matter. <span>If the concentration of the KMnO4 solution is important (usually in titrations etc.) then it is not allowed to use a wet bottle. The water in the bottle will dilute the KMnO4 solution and change the concentration of the said compound.</span>
