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olasank [31]
1 year ago
7

If a hyperpolarizing graded potential and a depolarizing graded potential of similar magnitudes arrive at the trigger zone at th

e same time, what is most likely to occur
Physics
1 answer:
Flura [38]1 year ago
8 0

The likely outcome when a hyperpolarizing and a depolarizing potential of similar magnitudes arrive simultaneously at the trigger zone is the cancellation of charges.

<h3>What is membrane action potential?</h3>

Membrane action potential refers to differential electric charges within and outside of a given cell.

Hyperpolarization refers to a differential membrane potential of a cell associated with a negative charge, whereas depolarization is associated with a positive charge.

In conclusion, the likely outcome when a hyperpolarizing and a depolarizing potential of similar magnitudes arrive simultaneously at the trigger zone is the cancellation of charges.

Learn more about membrane action potential here:

brainly.com/question/6705448

#SPJ1

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Why does the current splits in parallel circuit and why does the voltage remains equal?​
Xelga [282]

<u>Voltage:</u>

It is basically the difference between the charges of the materials on the ends of the Wire

<em>also known as potential difference</em>

It is very similar to the movement of air, it moves from higher density to lower density. in this case, the change in density is the potential difference

So, since voltage is the difference between the charge available on the ends of a wire. Even if the wire splits in parallel circuit, the difference of the charges remains the same

<em>the more the potential difference, the faster electrons will move to the material with lower charge</em>

<u>Current:</u>

Current is the amount of electrons moving through a cross-section of a wire in a period of time

So basically, it is the amount of electrons that move across a given point on a wire in a period of time

If the wire splits, we will have the same amount of electrons moving through as they would if the wire was not split but now, the electrons passing are divided and hence, if we measure the current after the split, we will find that we have a lower current

that's because we have less charge moving through the cross-section of the wire since some of those electrons are moving through a different wire

That's why the current splits in a parallel circuit

3 0
2 years ago
A car is moving in the positive direction along a straight highway and accelerates at a constant rate while going from point A t
rusak2 [61]

Answer:

The time where the avergae speed equals the instaneous speed is T/2

Explanation:

The velocity of the car is:

v(t) = v0 + at

Where v0 is the initial speed and a is the constant acceleration.

Let's find the average speed. This is given integrating the velocity from 0 to T and dividing by T:

v_{ave} = \frac{1}{T}\int\limits^T_0 {v(t)} \, dt

v_ave = v0+a(T/2)

We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>

v(T/2)=v_ave

Now we want to know where the car should be, the osition of the car is:

x(t) = x_A + v_0 t + \frac{1}{2}at^2

Where x_A is the position of point A. Therefore, the car will be at:

<u><em>x(T/2) = x_A + v_0 (T/2) + (1/8)aT^2</em></u>

8 0
2 years ago
A rope is being used to pull a mass of 10 kg vertically upward. Determine the tension on the rope, if starting from rest, the ma
Sergio [31]

Answer:

mgh= 10 x 8 x 10

= 800

but you can try 10 x 8 x 4^-1 x 10

6 0
2 years ago
A car of mass m goes around a banked curve of radius r with speed v. If the road is frictionless due to ice, the car can still n
Sholpan [36]

Answer:

horizontal component of normal force is equal to the centripetal force on the car

Explanation:

As the car is moving with uniform speed in circle then the force required to move in the circle is towards the center of the circle

This force is due to friction force when car is moving in circle with uniform speed

Now it is given that car is moving on the ice surface such that the friction force is zero now

so here we can say that centripetal force is due to component of the normal force which is due to banked road

Now we have

N sin\theta = \frac{mv^2}{R}

N cos\theta = mg

so we have

v = \sqrt{Rg tan\theta}

so this is horizontal component of normal force is equal to the centripetal force on the car

5 0
3 years ago
Which of the following statement describes an actual orbit
Leno4ka [110]

I suppose right answer is d because staellite means an object that move around the larger object and Jupiter also moves around the Sun

7 0
3 years ago
Read 2 more answers
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