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olasank [31]
2 years ago
7

If a hyperpolarizing graded potential and a depolarizing graded potential of similar magnitudes arrive at the trigger zone at th

e same time, what is most likely to occur
Physics
1 answer:
Flura [38]2 years ago
8 0

The likely outcome when a hyperpolarizing and a depolarizing potential of similar magnitudes arrive simultaneously at the trigger zone is the cancellation of charges.

<h3>What is membrane action potential?</h3>

Membrane action potential refers to differential electric charges within and outside of a given cell.

Hyperpolarization refers to a differential membrane potential of a cell associated with a negative charge, whereas depolarization is associated with a positive charge.

In conclusion, the likely outcome when a hyperpolarizing and a depolarizing potential of similar magnitudes arrive simultaneously at the trigger zone is the cancellation of charges.

Learn more about membrane action potential here:

brainly.com/question/6705448

#SPJ1

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A EXAMPLE OF WHEN BOTH PHYSICAL CHANGE AND CHEMICAL CHANGE OCCUR 3 EXAMPLES
kvasek [131]

Answer:

I know 1, that is in the case of a burning of a candle.

Explanation:

5 0
3 years ago
A car speedometer has a 4% uncertainty. What is the range of possible speeds (in km/h) when it reads 110 km/h?
Kruka [31]
4% of 110 is 4.4. So the possible range of speeds is the interval from 110-4.4 till 110+4.4.
105.6 till 114.4
4 0
3 years ago
Two football players are pushing a 60 kg blocking sled across the field at a constant speed of 2.0 m/s. The coefficient of kinet
MArishka [77]

Answer:

The sled slides d=0.155 meters before rest.

Explanation:

m= 60 kg

V= 2 m/s

μ= 0.3

g= 9.8 m/s²

W= m * g

W= 588 N

Fr= μ* W

Fr= 176.4 N

∑F = m * a

a= (W+Fr)/m

a= 12.74m/s²

t= V/a

t= 0.156 s

d= V*t - a*t²/2

d= 0.155 m

7 0
3 years ago
If the load distance of a lever is 30 cm and the effort distance is 60 cm, calculate the amount of effort required to lift a loa
vladimir2022 [97]

Here,

Load distance (Ld) = 30 cm

Effort distance (Ed) = 60 cm

Load (L) = 200N

Effort (E) = ?

Now, By using formula,

or, E * Ed = L * Ld

or, E * 60 = 200 * 30

or, E = 6000/60

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This is a Right answer...

I hope you understand...

7 0
3 years ago
Two electrodes, separated by a distance d, in a vacuum are maintained at a constant potential difference. An electron, accelerat
Alja [10]

Answer:

Explanation:

Given that, the distance between the electrode is d.

The electron kinetic energy is Ek when the electrode are at distance "d" apart.

So, we want to find the K.E when that are at d/3 distance apart.

K.E = ½mv²

Note: the mass doesn't change, it is only the velocity that change.

Also,

K.E = Work done by the electron

K.E = F × d

K.E = W = ma × d

Let assume that if is constant acceleration

Then, m and a is constant,

Then,

K.E is directly proportional to d

So, as d increase K.E increase and as d decreases K.E decreases.

So,

K.E_1 / d_1 = K.E_2 / d_2

K.E_1 = E_k

d_1 = d

d_2 = d/3

K.E_2 = K.E_1 / d_1 × d_2

K.E_2 = E_k × ⅓d / d

Then,

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So, the new kinetic energy is one third of the E_k

7 0
3 years ago
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