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olasank [31]
2 years ago
7

If a hyperpolarizing graded potential and a depolarizing graded potential of similar magnitudes arrive at the trigger zone at th

e same time, what is most likely to occur
Physics
1 answer:
Flura [38]2 years ago
8 0

The likely outcome when a hyperpolarizing and a depolarizing potential of similar magnitudes arrive simultaneously at the trigger zone is the cancellation of charges.

<h3>What is membrane action potential?</h3>

Membrane action potential refers to differential electric charges within and outside of a given cell.

Hyperpolarization refers to a differential membrane potential of a cell associated with a negative charge, whereas depolarization is associated with a positive charge.

In conclusion, the likely outcome when a hyperpolarizing and a depolarizing potential of similar magnitudes arrive simultaneously at the trigger zone is the cancellation of charges.

Learn more about membrane action potential here:

brainly.com/question/6705448

#SPJ1

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Minchanka [31]

Answer:

B)

Explanation:

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5 0
3 years ago
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Exactly one pound of bread dough is placed in a baking tin. the dough is cooked in an oven at 350 °f releasing a wonderful aroma
Sladkaya [172]
The mass of the baked loaf will be less than the original dough. In making dough for bread, we have ingredients that are liquid such as water, melted butter, food flavoring, etc. All of this liquid ingredients mixed on the dough will definitely turn into vapor. This vapor is responsible for releasing of the aroma of the freshly baked bread.
7 0
3 years ago
A hammer slides down a roof that makes a 30.0°angle with the horizontal. What are the magnitudes of the components of the hammer
dlinn [17]
<h2>Answer:7.14ms^{-1},4.125ms^{-1}</h2>

Explanation:

Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.

One of such independent 1D frames are along horizontal and another along vertical.

Let v be the total velocity.

Given that,v=8.25ms^{-1}

We call the horizontal velocity as v_{h} and the vertical velocity as v_{v}.

v_{h}=vCos\alpha

v_{v}=vSin\alpha

where \alpha is the angle between the object and horizontal.

It is given that \alpha =30^{0}

v_{h}=8.25\times Cos(30^{0})=7.14ms^{-1}

v_{v}=8.25\times Sin(30^{0})=4.125ms^{-1}

7 0
3 years ago
The speed of a tennis ball that is served is 73.14 m/s. During a serve, the ball typically starts from rest and is in contact wi
Serga [27]

Answer: Third option

F = 250w

Explanation:

The impulse can be written as the product of force for the time interval in which it is applied.

I = F (t_2-t_1)

You can also write impulse I as the change of the linear momentum of the ball

I = mv_2 -mv_1

So:

F (t_2-t_1) = mv_2 -mv_1

We want to find the force applied to the ball. We know that

(t_2-t_1) = 30 milliseconds = 0.03 seconds

The initial velocity v_1 is zero.

The final speed v_2 = 73.14\ m / s

So

F * 0.03 = 73.14m

F * 0.03 = 73.14m\\\\F=\frac{73.14m}{0.03}\\\\F=2438m

We must express the result of the force in terms of the weight of the ball.

We divide the expression between the acceleration of gravity

g = 9.8\ m / s ^ 2

F=\frac{2438m*g}{g},\ \ m*g=w\\\\g=9.8\ m/s^2\\\\F=\frac{2438w}{9.8}\\\\F=249w

The answer is the third option

3 0
3 years ago
How do you rationalize the tension being used in Tennis Racket strings using the concept of impulse and momentum?
zheka24 [161]

Answer:

The momentum, ΔP, and therefore, kinetic energy given to the ball in a serve is the result of the product of the tension force, 'F', in the string and the time of contact, Δt, between the ball and the string

ΔP = F × Δt

Explanation:

The impulse, ΔP, is the produce of the force, 'F', applied to a body for a given period of time, Δt', that gives motion to the body, and it is equal to the change of momentum of the body

ΔP = F × Δt

The momentum, 'P', of a body is the product of the mass, 'm', of the body and its velocity, 'v'

P = m × v

Tension is the axial pulling force of a string

T = Axial Force, F_{axial}

The tension used in Tennis Racket strings is between 40 to 65 lbs.

When high tension is used in the string, the string is taut, and the contact duration between the Racket string and the ball is minimal, and the player needs to use more force to obtain a high momentum, and therefore, energy in the ball, which reduces control, and increase stress, as force is more emphasized

When low tension is used in the string, the Tennis Racket strings are more elastic. During a serve, the ball pushes the strings further back into the racket, such that the ball spends more time in contact with the string, (Δt is larger), and therefore, the impulse, F·Δt = ΔP, given to the ball is larger, therefore, the ball has a larger change in momentum, and therefore more energy in the intended direction.

However, a very slackened string will increase the increase area and time (large Δt) of contact of the ball and the racket such that the force given to the ball, F = ΔP/(large Δt) is reduced and therefore reduce the likelihood of gaining points from a serve against an opponent with a much forceful return of a serve.

3 0
3 years ago
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