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vazorg [7]
3 years ago
11

Nora tied a string around a tennis ball, and then she swung it in a circle in front of her to demonstrate a planet orbiting the

Sun. She explained that her hand represented the Sun, the ball represented a planet, and the string kept the ball from leaving the "orbit" around her hand. Why doesn't the string work in the same way as gravity? A. The string holding the ball in orbit is a contact force; gravity is a noncontact force. B. The string only pulls one way; gravity pulls both ways. C. The string keeps the distance between the bodies the same; gravity makes the distance vary. D. There is no difference between the two systems.
Physics
2 answers:
777dan777 [17]3 years ago
8 0

<em>Choice-A </em>is a true statement. The string holding the ball in orbit is a contact force, whereas gravity is a non-contact force.

Choice-C is half-true.  The string keeps the distance between the bodies constant, but gravity doesn't "MAKE" the distance vary.

shutvik [7]3 years ago
5 0

Answer:The string holding the ball in orbit is a contact force; gravity is a noncontact force.

Explanation:

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Two cars are moving towards each other and sound emitted by first car with real frequency of 3000 hertz is detected by a person
sertanlavr [38]

Answer:

 v ’= 21.44 m / s

Explanation:

This is a doppler effect exercise that changes the frequency of the sound due to the relative movement of the source and the observer, the expression that describes the phenomenon for body approaching s

           f ’= f (v + v₀) / (v-v_{s})

where it goes is the speed of sound 343 m / s, v_{s} the speed of the source v or the speed of the observer

in this exercise both the source and the observer are moving, we will assume that both have the same speed,

                v₀ = v_{s} = v ’

we substitute

               f ’= f (v + v’) / (v - v ’)

               f ’/ f (v-v’) = v + v ’

               v (f ’/ f -1) = v’ (1 + f ’/ f)

               v ’= (f’ / f-1) / (1 + f ’/ f) v

               v ’= (f’-f) / (f + f’) v

let's calculate

                v ’= (3400 -3000) / (3000 +3400) 343

                v ’= 400/6400 343

                v ’= 21.44 m / s

3 0
3 years ago
How is frame motion used to measure motion
Mice21 [21]

Answer:

To describe motion accurately and completely, a frame of reference is necessary. frame of reference ( or reference frame) consists of an abstract coordinate system and the set of physical reference points that uniquely fix ( locate and orient ) the coordinate system and standardize measurements within that frame.

Explanation:

The different observations occur because the two observers are in different frames of reference. A frame of reference is a set of coordinates that can be used to determine positions and velocities of objects in that frame; different frames of reference move relative to one another.

8 0
2 years ago
2. Light with a wavelength of 478 nm lies in the blue region of the visible spectrum. Calculate the frequency of this light.
Feliz [49]

Answer:

I GUESS 204 MPHN

Explanation:

4 0
3 years ago
Two trains traveling on parallel tracks are going toward each other from a distance of 552 miles. If the freight train is moving
irga5000 [103]

Answer:

6hrs

Explanation:

t = time taken until the trains pass by each other/hrs

38 + 54 = 92

Use time = distance/speed:

t = 552/92 = 6

3 0
3 years ago
If conducted accurately, identical investigations should produce similar results. Sometimes, errors, like measurement errors, ca
Flura [38]

Answer: A) Sandra discovered several rabbits had been munching on her pea plants, while Jeremy had none.

Explanation:

3 0
3 years ago
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