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4 years ago

Special relativity cannot be used to study an object in which frame of reference

Physics

2 answers:

Luba_88 [7]4 years ago

6 0

The question is incomplete. The complete question is:

Special relativity cannot be used to study an object in which frame of reference?

A. A frame of reference that has no change in velocity

B. A frame of reference that is moving in a circle

C. A frame of reference that has a constant, positive acceleration

D. A frame of reference that has a constant, negative acceleration

Answer:

A frame of reference that has a constant, positive acceleration

A frame of reference that has a constant, negative acceleration

Explanation:

Special relativity applies to frames of reference in which an object is moving at constant velocity.

If the velocity is constant, it implies that acceleration will be zero hence options C and D will be correct since they both involve a non-zero change in velocity.

Phoenix [80]4 years ago

4 0

Special relativity can be used to study an object in which frame of reference ... C. A frame of reference that has a constant, positive acceleration.

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Calculate the force of attraction between

vagabundo [1.1K]

Answer:

So the force of attraction between the two objects is 3.3365*10^-6

Explanation:

m1=10kg

m2=50kg

d=10cm=0.1m

G=6.673*10^-11Nm^2kg^2

We have to find the force of attraction between them

F=Gm1m2/d^2

F=6.673*10^-11*10*50/0.1^2

F=3.3365*10^-8/0.01

F=3.3365*10^-6

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4 years ago

How can you determine that a coin

OleMash [197]

Answer:

by checking if its malleble with a hammer

Explanation:

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3 years ago

Thomas threw a ball down a pit that was 400m deep. a) How long did it take to land? b) What speed was it going when it landed?

bulgar [2K]

Hi there!

We can use the equation t = √2d/g to solve. (Let's let g = 10 m/s²)

**How to get this equation**

We have the equation:

Δd = vit + 1/2at²

For freefall, we know that vi = 0, so we are left with:

Δd = 1/2at²

We know that a = g. Rearrange in terms of t:

2Δd / a = t²

Square root both sides:

√(2d/a) = t

Plug in the height and gravity:

t = √2(400)/10 = √800/10 = √80 ≈ 8.94 sec

Find the final speed using the following formula:

vf = √2gd

**How to derive**

We know the equation:

vf² = vi² + 2ad

vi = 0, so:

vf² = 2ad

Square root both sides:

vf = √2ad

vf = √2(400)(10) = √8000 ≈ 89.44 m/s

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3 years ago

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olga nikolaevna [1]

Answer: the amount of precious metals that could be had.

<span>Mercantilism believed that a nation was rich based on how big their reserves were for precious metals like gold and silver. Exporting lots of gold and silver, during the time mercantilism was in place as an economic system, exhibited a nation’s wealth. </span>

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3 years ago

Read 2 more answers

4. Next discuss how Dr. Knappe used technology to measure how fast the tectonic plates are

wariber [46]

Answer:

She used the Global Positioning System.

Explanation:

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3 years ago