Answer:
sound wave-electrical wave-radio wave
Answer:
a. Load.
b. Fuse.
c. Source.
d. Wire.
e. Switch.
Explanation:
An electric circuit can be defined as an interconnection of electrical components which creates a path for the flow of electric charge (electrons) due to a driving voltage.
Generally, an electric circuit consists of electrical components such as resistors, capacitors, battery, transistors, switches, inductors, fuse, etc.
Matching the given circuit parts to their appropriate functions, we have;
a. Load: an appliance or device that uses electricity source like bulbs, computers, television, radio, etc.
b. Fuse: it is a safety device made from materials that easily melt even before the wires carry too much current.
c. Source: it is where electricity came from like batteries and generators.
d. Wire: it is the pathway of electricity from the resources (source) to the load.
e. Switch: it controls the flow of electricity from the source. It is typically used to turn ON or turn OFF a load.
Weak nuclear force is the most involved
A. Relaxing under a tree.
The parasympathetic nervous system is known as the “rest and digest” system. Activities that require as little movement as possible help the heart rate to slow down. The other activities would be associated with the Sympathetic nervous system which is known as the “fight or flight,” or when your heart rate is up and running.
The lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
To find the answer, we need to know about the Newton's equation of motion.
<h3>What's the Newton's equation of motion to find the acceleration in term of initial velocity, final velocity and distance?</h3>
- The Newton's equation of motion that connects velocity, distance and acceleration is V² - U²= 2aS
- V= final velocity, U= initial velocity, S= distance and a= acceleration
<h3>What's the acceleration, if the initial velocity, final velocity and distance are 0 m/s, 360km/h and 1.8 km respectively?</h3>
- Here, S= 1.8 km or 1800 m, V= 360km/h or 100m/s , U= 0 m/s
- So, 100²-0= 2×a×1800
=> 10000= 3600a
=> a= 10000/3600 = 2.8 m/s²
Thus, we can conclude that the lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
Learn more about the Newton's equation of motion here:
brainly.com/question/8898885
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