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dangina [55]
3 years ago
13

What is altered by a catalyst?

Chemistry
2 answers:
JulsSmile [24]3 years ago
7 0

Answer:Effect of Catalysts on the Activation Energy. Catalysts provide a new reaction pathway in which a lower Activation energy is offered. A catalyst increases the rate of a reaction by lowering the activation energy so that more reactant molecules collide with enough energy to surmount the smaller energy barrier.

Explanation:

Your answer is in this

cupoosta [38]3 years ago
7 0

Answer:

B

Explanation:

A catalyst can speed up the reaction (or make it initaite easier) by altering the activation energy.

You might be interested in
How many grams of Co3+ are present in 2.34 grams of cobalt(III) nitrite?
Assoli18 [71]

Answer:

m_{Co^{3+}}=0.563gCo^{3+}

Explanation:

Hello there!

In this case, since these mole-mass relationships are understood in terms of the moles of the atoms forming the considered compound, we first realize that the chemical formula of the cobalt (III) nitrate is Co(NO₃)₃ whereas there is a 1:1 mole ratio of the cobalt (III) ion (molar mass = 58.93 g/mol) to the entire compound. In such a way, we first compute the moles of the salt (molar mass = 58.93 g/mol) and then apply the aforementioned mole ratio to obtain the grams of the required cation:

m_{Co^{3+}}=2.34gCo(NO_3)_3*\frac{1molCo(NO_3)_3}{244.95 gCo(NO_3)_3} *\frac{1molCo^{3+}}{1molCo(NO_3)_3} *\frac{58.93gCo^{3+}}{1molCo^{3+}} \\\\m_{Co^{3+}}=0.563gCo^{3+}

Best regards!

4 0
2 years ago
Cyclopropene decomposes to propene when heated to 500 C, calculate rate constant for the first order reaction 0 min 1.48 mmol/L
Dmitry_Shevchenko [17]

Answer:

k = 0.0306 min-1

Explanation:

The table is given as;

Time, Concentration

0 1.48

5 1.27

10 0.98

15 0.84

The integrated rate law for a first order reaction is given as;

ln [A] = -kt + ln [Ao]

where;

[A] = Final Concentration

[Ao] = Initial Concentration

k = rate constant

t = time

In the table, taking the first two sets of values;

t = 5

k = ?

[Ao]  = 1.48

[A] = 1.27

Inserting into the equation;

ln(1.27) = - k (5) + ln(1.48)

ln(1.27)  - ln(1.48) = -5k

-0.1530 = -5k

k = -0.1530 / -5

k = 0.0306 min-1

6 0
3 years ago
A 3000 MWt fast reactor has a 42% efficiency. This reactor operates for 23 months followed by a 1 month down time for refueling
n200080 [17]

Answer:

capacity factor = 0.952

Availability factor = 0.958

Explanation:

1) capacity factor

capacity factor = actual power output /  maximum power output

                        = (actual power output)/(efficiency * rated power output)

                       = \frac{1200}{\frac{42}{100}*3000}

= 0.952

2) Availability factor

Availability factor  = Actual operation time period/ total time period

                            = 23/24 = 0.958

8 0
3 years ago
Rozwiaz logogryf. Z wyróżnionych pól odczytaj hasło i je zapisz.
saul85 [17]

Answer:

1) Nitrogen

2) Methane

3) Dipeptide

4) Ammonia

5) Glycine

In Polish/Po polsku

1) Azot

2) metan

3) dipeptyd

4) Amoniak

5) glicyna

Explanation:

English Translation

Solve logogriffs. Read the password from the highlighted fields and write it down.

1.The chemical element being the main component of air (it occupies 78% of its volume),

2. The simplest saturated hydrocarbon,

3. Is a result of combining two amino acid molecules,

4. Gas with a pungent odor, soluble in water; hydrogen and nitrogen synthesis product.

5. Common name of aminoacetic acid

(the first has four boxes, the second has five boxes, the third has eight quarters has seven, fifths and seven).

Thank you in advance

1) The main component of air that makes up 78% of the air is Nitrogen.

2) The simplest saturated hydrocarbon is the first member of the alkane family, Methane.

3) Two amino acids combine by forming peptide bonds between the carboxyl group of one amino acid and the amino group of another through dehydration synthesis (loss of 1 molecule of water). Hence, the result of the combination of two amino acids are called Dipeptides.

4) Nitrogen and Hydrogen come together to form only one known water soluble gas with pungent smell, called Ammonia.

5) Aminoacetic acid as its name suggests is an amino acid with the acetyl group. It is the simplest amino acid. The common name for this compound is Glycine.

In Polish/Po polsku

1) Głównym składnikiem powietrza, które stanowi 78% powietrza, jest azot.

2) Najprostszym nasyconym węglowodorem jest pierwszy członek rodziny alkanów, metan.

3) Dwa aminokwasy łączą się, tworząc wiązania peptydowe między grupą karboksylową jednego aminokwasu i grupą aminową innego przez syntezę odwodnienia (utrata 1 cząsteczki wody). Stąd wynik połączenia dwóch aminokwasów nazywa się dipeptydami.

4) Azot i wodór tworzą razem jeden znany gaz rozpuszczalny w wodzie o ostrym zapachu, zwany amoniakiem.

5) Kwas aminooctowy, jak sama nazwa wskazuje, jest aminokwasem z grupą acetylową. To najprostszy aminokwas. Powszechna nazwa tego związku to glicyna.

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

8 0
3 years ago
When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr
konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

4 0
3 years ago
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