Using the mass/volume percentage method for percentages of the solution, you simply divide the grams of solute by the volume of the solution and multiply by 100 to get your percentage.
(75.0g/250mL)•100 = 30.0% solute
Answer:
0.7 g/cm³
Explanation:
<em>hey there,</em>
<em />
< The formula for density is
where m = mass, v = volume, and p = density. An easy way to remember the formula is density equals love. I found this easy to remember because p = ♡ and when you think about it, if you split the heart in half through the middle like a fraction, it will make
(if you don't understand what I'm saying, try writing it out and you will be able to see what I'm talking about!)
We already know that the block is 253 g so the mass is 253 g.
To find the volume, always multiply the 3 values width, length, and height whenever you are trying to find the volume of a block.
15.24 cm x 6.64 cm x 3.56 cm = 360.25 cm³
Now plug it into the formula.
³ >
<u>Hope this helped! Feel free to ask anything else.</u>
Answer:
I believe it is "Arsenenate"
Answer: X3Y2
Explanation:
The formula is
X has a valency of 2
Y has a valency of 3
So, we interchange the valencies
Therefore, the formula is
X3Y2
Answer:Gained, Lost , Shared
Explanation:
The oxidation state tells you how many electrons an atom has GAINED.................. , LOST....................... , or SHARED........................ , in forming a compound.
Oxidation state is defined as the the total number of electrons that an atom gains or loses when forming a chemical bond with another atom.
----To form an ionic bond for example in NaCl, Na, with 11 electrons and one valence electron in its outermost shell donates or lose that valence electron to Chlorine with 17 electron and 7 in its outermost shell. Therefore Sodium, Na acquires the +1 oxidaton state to become stable and Chlorine acquires the -1 oxidation state to become stable forming the NaCl compound.
To form a covalent compound, There must be sharing of electrons between atoms.For example, in PCl3, The phosphorous atom with atomic number 15 shares its three unpaired electrons with the single valence electrons of three chlorine atoms. making the four molecules to attain stability with Phosphorous having +3 and the chlorine atoms having -1 oxidation states