<h3>Answer:</h3>
Limiting reactant is Lithium
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of Lithium as 1.50 g
- Mass of nitrogen is 1.50 g
We are required to determine the rate limiting reagent.
- First, we write the balanced equation for the reaction
6Li(s) + N₂(g) → 2Li₃N
From the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
- Second, we determine moles of Lithium and nitrogen given.
Moles = Mass ÷ Molar mass
Moles of Lithium
Molar mass of Li = 6.941 g/mol
Moles of Li = 1.50 g ÷ 6.941 g/mol
= 0.216 moles
Moles of nitrogen gas
Molar mass of Nitrogen gas is 28.0 g/mol
Moles of nitrogen gas = 1.50 g ÷ 28.0 g/mol
= 0.054 moles
- According to the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
- Therefore, 0.216 moles of lithium will require 0.036 moles (0.216 moles ÷6) of nitrogen gas.
- On the other hand, 0.054 moles of nitrogen, would require 0.324 moles of Lithium.
Thus, Lithium is the limiting reagent while nitrogen is in excess.
<span>A submerged object displaces a volume of liquid equal to the volume of the object. One milliliter (1 mL) of water has a volume of 1 cubic centimeter (1cm3).</span>
Inert properties
<span>Nitrogen is used to protect steel from water because it has inert properties that make it a good blanketing gas.</span>
Answer:
w w w . g o o g l e . c o m
Explanation:
Ammonia yields nitric oxide and water in the presence of oxygen. The mass of nitric acid that will be produced from 6.40 gm of oxygen is 4.8 grams.
<h3>What is mass?</h3>
Mass is the product of the moles of the substance and its molar mass. it is given as,
The balanced chemical reaction is shown as:
Moles of oxygen are calculated by mass, 6.40 gm as,
From the reaction, the molar ratio of nitric oxide to oxygen is 4: 5 and is used to calculate the moles of nitric oxide as,
0.16 moles and molar mass, 30 of nitric oxide is used to calculate the mass as,
Therefore, 4.8 grams of nitric oxide will be produced.
Learn more about mass here:
brainly.com/question/4264188
#SPJ4
