Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics

2 answers:

natima [27]3 years ago

8 0

Answer:

dependent

Step-by-step explanation:

These two events are dependent. When the ball is set aside, there are fewer balls to draw from, so the probability of getting a certain ball becomes greater.

Vlada [557]3 years ago

8 0

<h3>Answer: Dependent</h3>

Why is this?

The first selection affects the probability of the second selection.

Let's say we had 10 numbers to pick from: {1,2,3,4,5,6,7,8,9,10}

The probability of getting any single number is 1/10 = 0.10 = 10%

After that first ball is picked, and not put back (thats the key here), we have 9 balls left. The probability of getting a single number from this new reduced set is 1/9 = 0.111 = 11.1% approximately. We have a slightly higher chance to get a certain number compared to than before. This is because there is a smaller pool to pick from. The second selection's probability being changed based on the first event is why the second event is dependent on the first. The events would only be independent if the second probability does not change no matter what the first event does.

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sertanlavr [38]

Graphically is intersect i believe

6 0

2 years ago

Find the distance points p (3,6) and q (7,3) to the nearest tenth?

Vladimir79 [104]

<h3>Answer: 5</h3>

=========================================================

One method is to plot the points P(3,6) and Q(7,3) on the same xy grid. Plot a third point R at (3,3). See the diagram below.

A right triangle forms in which we can find the legs PR = 3 and RQ = 4. The hypotenuse is found through the pythagorean theorem.

a^2+b^2=c^2

3^2+4^2 = c^2

9+16 = c^2

c^2 = 25

c = sqrt(25)

c = 5

This is the length of PQ

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Or you can use the distance formula which is effectively using the pythagorean theorem just in a slightly different format (though it may not be obvious).

$d = \text{Distance from P to Q}\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(3-7)^2+(6-3)^2}\\\\d = \sqrt{(-4)^2+(3)^2}\\\\d = \sqrt{16+9}\\\\d = \sqrt{25}\\\\d = 5\\\\$