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forsale [732]
3 years ago
6

A) NaCl2 b) Al3Br c) AlO2 d) H2Br e) CaCl2

Chemistry
1 answer:
Elena L [17]3 years ago
3 0
The answer to this question is C) ALO2
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What is the electrical charge of a cation?<br> A. zero<br> B. positive<br> C. negative
Ronch [10]
It would be letter "B", positive. Anions are the ones with negative charges.
6 0
3 years ago
If someone consumes 22 g of sodium chloride per day, what mass (in grams) of sodium does that person consume? Sodium chloride is
kompoz [17]

Answer:

Mass of sodium, the person daily consume = 8.58 g

Explanation:

Given that:-

sodium chloride is 39% sodium by mass which means that:-

100 g of sodium chloride contains 39 g of sodium

Also,

1 g of sodium chloride contains 0.39 g of sodium

So, Given mass = 22 g

22 g of sodium chloride contains 0.39\times 22 g of sodium

<u>Mass of sodium, the person daily consume = 8.58 g</u>

4 0
3 years ago
Which is an example of how people use nonrenewable energy resources?
Arturiano [62]

Answer:

i dont think its walking to school because that doesn't use any resources.

Explanation:

i think its driving a car because we use gasoline for that and for sailing we use the wind. hopefully that helps.

7 0
2 years ago
I need help with this question ​
VARVARA [1.3K]

Answer:

2.25×10¯³ mm.

Explanation:

From the question given above, we obtained the following information:

Diameter in micrometer = 2.25 μm

Diameter in millimetre (mm) =?

Next we shall convert 2.25 μm to metre (m). This can be obtained as follow:

1 μm = 1×10¯⁶ m

Therefore,

2.25 μm = 2.25 μm / 1 μm × 1×10¯⁶ m

2.25 μm = 2.25×10¯⁶ m

Finally, we shall convert 2.25×10¯⁶ m to millimetre (mm) as follow:

1 m = 1000 mm

Therefore,

2.25×10¯⁶ m = 2.25×10¯⁶ m /1 m × 1000 mm

2.25×10¯⁶ m = 2.25×10¯³ mm

Therefore, 2.25 μm is equivalent to 2.25×10¯³ mm.

6 0
3 years ago
Soil that is damaged and loses its nutrients is quick to regain nutrients.
Amiraneli [1.4K]

Answer:

false,soil damage and nutrient loss can be a major problem so it can not gain nutrients quickly

6 0
2 years ago
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