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4 years ago

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A student placed 11.0 g of glucose (C6H12O6 ) in a volumetric flask, added enough water to dissolve the glucose by swirling, the

n carefully added additional water until the 100. mL mark on the neck of the flask was reached.
The flask was then shaken until the solution was uniform. A 55.0 mL sample of this glucose solution was diluted to 0.500 L .

How many grams of glucose are in 100. mL of the final solution?

1 answer:

Sedaia [141]4 years ago

4 0

Answer:

We have 12.1 grams of glucose in 100 mL of solution

Explanation:

Step 1: Data given

Mass of glucose = 11.0 grams

Volume = 100 mL

A 55.0 mL sample of this glucose solution was diluted to 0.500 L .

Step 2: Calculate concentration of glucose

Initially, amount of glucose available in 100 ml of the solution = 11.0 grams

Concentration of glucose = mass/ volume

Concentration=11.0 /0.100

= 110 g/L

We take away, 0.055 L of that solution, creating another solution with it but with 0.500 L of volume

Step 3: calculate concentration of the new volume

⇒ with C1 = Concentration of the first solution

⇒ with V1 = Volume of the first solution

⇒ with C2 = Concentration of the second solution

⇒ with V2 = Volume of the second solution

C1V1= C2V2

110 * 0.055= C2 * 0.500

= 12.1 g/L -= the concentration of the new solution

Step 4: Calculate the mass in 0.100 L

Concentration = mass/ volume

12.1 = mass/0.100

=1.21 grams

We have 12.1 grams of glucose in 100 mL of solution

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