Answer:
Explanation:
This question asks us to find the new volume if the pressure changes. Therefore, we use Boyle's Law, which states that pressure and the volume of the gas are inversely proportional. The formula is:
We know that the original sample of gas occupies 4.5 liters at a pressure of 1.63 atmospheres. We know that the pressure was changed to 2.4 atmospheres, but we don't know the volume. Substitute all known values into the formula.
Since we are solving for the new volume (V₂), we need to isolate the variable. It is being multiplied by 2.4 atmospheres and the inverse of multiplication is division. Divide both sides by 2.4 atm.
The units of atmospheres (atm) cancel.
The smallest number of significant figures in the original measurements is 2, so our answer must have the same. For the number we found, that is the tenths place.
The 5 in the hundredth place tells us to round the 0 up to a 1.
The volume of the neon gas when the pressure is changed to 2.4 atmospheres is <u>3.1 Liters.</u>
Answer:
Option B is the most correct.
If a system loses energy to the surroundings, then the surroundings must do an equal amount of work on the system. if the surroundings gain energy from the system, then the system must lose an equal amount of energy.
Explanation:
The first law of thermodynamics is the law of conservation of energy. It explains that energy can neither be created nor destroyed, but can only be transformed from one form to another of transferred from one place to another (In various forms at times).
So, if a system gains energy from the surroundings, it is evident that this energy wasn't created, it was transferred in from the surroundings, meaning that the surroundings have lost that same amount of energy and vice versa.
So, it is obvious why option B is the most correct of all the options.
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Answer:
true
Explanation:
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Answer:
Explanation:
We are given the amounts of two reactants, so this is a limiting reactant problem.
1. Assemble all the data in one place, with molar masses above the formulas and other information below them.
Mᵣ: 58.44
NaCl + AgNO₃ ⟶ NaNO₃ + AgCl
m/g: 0.245
V/mL: 50.
c/mmol·mL⁻¹: 0.0180
2. Calculate the moles of each reactant
3. Identify the limiting reactant
Calculate the moles of AgCl we can obtain from each reactant.
From NaCl:
The molar ratio of NaCl to AgCl is 1:1.
From AgNO₃:
The molar ratio of AgNO₃ to AgCl is 1:1.
AgNO₃ is the limiting reactant because it gives the smaller amount of AgCl.
4. Calculate the moles of excess reactant
Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)
I/mmol: 0.900 4.192 0
C/mmol: -0.900 -0.900 +0.900
E/mmol: 0 3.292 0.900
So, we end up with 50. mL of a solution containing 3.292 mmol of Cl⁻.
5. Calculate the concentration of Cl⁻
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