Answer:
The distance the mass would stretch it is 
The correct option is A
Explanation:
From the question we are told that
The period of the slit is 
The acceleration due to gravity is 
Generally the period is mathematically represented as

Whee m is the particle and k is the spring constant
making
the subject
The weight on the particle is related to the force stretching the spring by this mathematical relation


where x is the length by which the spring is stretched

Substituting the equation above for 
![[\frac{T}{2 \pi} ]^2 = \frac{x}{g}](https://tex.z-dn.net/?f=%5B%5Cfrac%7BT%7D%7B2%20%5Cpi%7D%20%5D%5E2%20%3D%20%5Cfrac%7Bx%7D%7Bg%7D)
making x the subject
![x = g [\frac{T}{2 \pi} ]](https://tex.z-dn.net/?f=x%20%3D%20g%20%5B%5Cfrac%7BT%7D%7B2%20%5Cpi%7D%20%5D)
Substituting the value
![x = 9.8 * [\frac{0.2}{2 * 3.142} ]^2](https://tex.z-dn.net/?f=x%20%3D%209.8%20%2A%20%5B%5Cfrac%7B0.2%7D%7B2%20%2A%203.142%7D%20%5D%5E2)

The duration (i.e time) of the impact, given that the head impact was 1770 N is 0.005 s
<h3>How do I determine the duration (i.e time)?</h3>
Impulse is defined as the change in momentum of an object. It is expressed as:
Impulse = change in momentum
Impulse = final momentum – Initial momentum
Impule = m(v - u)
Impulse = force × time
Impulse = Ft
Thus,
Ft = m(v - u)
Where
- F is the force
- t is the time
- m is the mass
- u is the initial velocity
- v is the final velocity
Now, we can obtain the duration (i.e time) of the impact. Details below:
- Force (F) = 1770 N
- Initial velocity = 2.09 m/s
- Mass (m) = 4.12 Kg
- Final velocity = 0 m/s
- Duration (t) =?
Ft = m(v + u) since the collision came to a stop
1770 × t = 4.12 × (0 + 2.09)
1770 × t = 4.12 × 2.09
Divide both sides by 1770
t = (4.12 × 2.09) / 1770
t = 0.005 s
Thus, the duration is 0.005 s
Learn more about time:
brainly.com/question/64749
#SPJ1
Answer:
308,000 or 30.8×10^3
Explanation:
v=f×lamda
v is ?, f is 875Hz, lamda is 352m
v=875×352
v=308,000
v=30.8×10^3 m/s