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3 years ago

Where would a car traveling on a roller coaster have the most kinetic energy ? and why?

Physics

2 answers:

goldenfox [79]3 years ago

4 0

Answer:

As the car travels up the coaster it is gaining potential energy.

Explanation:

Because It has the greatest in amount of potential energy at the top of the coaster. when the car travels down the roller coaster it obtains speed and kinetic energy.

Soloha48 [4]3 years ago

3 0

Most potential energy at the top of a hill/loop and the most kinetic energy at the bottom of a hill/loop

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No work is said to be done by standing man carrying 500kg load.why?

Juli2301 [7.4K]

Answer:

no work is said to be done by standing man carrying 500kg load because

Explanation:

for the work to be done there should be two conditions i.e force should be applied and displacement must be covered.So for a man carring a 500 kg load force is there but he covers no distance by standing so displacement will be zero and since

work =force\displacement

displacement is zero so we can say that no work is done

7 0

2 years ago

Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x'(t) is its velocity, and x''

Lady_Fox [76]

Answer:

We know that the acceleration of the particle is defined as

$a(t)=\frac{dv}{dt}$

Since it is given that

$v(t)=\frac{5}{\sqrt{t}}\\\\\therefore a(t)=\frac{d(\frac{5}{\sqrt{t}})}{dt}\\\\a(t)=5\times \frac{dt^{-\frac{1}{2}}}{dt}\\\\=\frac{-5}{2}t^{\frac{-1}{2}-1}\\\\\therefore a(t)=x''(t)=\frac{-2.5}{t^{\frac{3}{2}}}$

Now by definition of velocity we have

$v(t)=\frac{dx(t)}{dt}\\\\\Rightarrow dx(t)=v(t)dt$

Integrating on both sides we get

$v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int v(t)dt$

Applying values we get

$v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int \frac{5}{t^{\frac{1}{2}}}dt\\\\\therefore x(t)=\frac{5}{0.5}\int t^{-0.5}dt\\\\x(t)=10\sqrt{t}+c$

To find the constant we note that at t=1 the particle is at x=12 Thus applying values in the above equation we get

$c=12-10\\\therefore c=2\\\\x(t)=10\sqrt{t}+2$

6 0

3 years ago

A solid wood door 1.00 m wide and 2.00 m high is hinged along one side and has a total mass of 45.0kg . Initially open and at re

aniked [119]

Answer:

0.19rad/s and Yes

Explanation:

From the principle of conservation of momentum it means momentum before and after collision is the same.

Momentum before collision is 0.700 kg×12 = 8.4Ns

Momentum of the door = mass of door × velocity of door

8.4Ns = mass of door × velocity of door

Velocity of door = 8.4Ns/45 =0.19m/s

But velocity V= w×r ;

w-angular velocity

r- raduis = width

w= 0.19/1m = 0.19rad/s

2. Yes it did because it resisted The moment of inertia and ensued the locking of the door.

5 0

3 years ago

What did Isaac Newton’s investigation if the gravity explain ?

Ludmilka [50]

Answer:

Gravity acts on all objects in the universe.

Explanation:

4 0

3 years ago

a high schooler who lives on the "5th" floor of an apartment complex dropped his phone off the balcony. If the balcony is 18.75

Airida [17]

Answer:

1.38 s

Explanation:

Use the free falling formula

T = √(L)/ g

T = √18.75/9.8

T = 1.38 s

7 0

3 years ago