1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
poizon [28]
3 years ago
8

Cuestionario:

Physics
1 answer:
Sati [7]3 years ago
3 0

Explanation:

1.El objetivo principal de realizar la llamada entrada en calor o calentamiento, es preparar el cuerpo para la actividad física o deportiva. Numerosas lesiones y ciertos problemas cardíacos como algunas arritmias, están asociados a la ejercitación violenta sin mediar un adecuado calentamiento.

You might be interested in
What are the 3 formulas you can use for vertical motion for a projectile?
klio [65]
I hope this can help you ask me if you need help again

4 0
3 years ago
A pulled tablecloth exerts a frictional force of 0.6 n on a plate with a mass of 0.4 kg. what is the acceleration of the plate?
Ludmilka [50]
The formula for acceleration is a = F/m; Where: F = force; m = mass
Given: F = .6n; m = .4kg; a = ?
a = F/m
  = .6/.4
  = 1.5

Therefore, the acceleration of the plate is 1.5 m/s^2
6 0
3 years ago
Which of the following statements is true about scientific theories?
artcher [175]
<span>d. scientific theories summarize patterns found in nature

Hope this helps!</span>
5 0
3 years ago
A test charge of 13 mC is at a point P where an external electric field is directed to the right and has a magnitude of 4 3 106
LenKa [72]

Answer:

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.

Explanation:

From coulomb's law, F = Eq

Thus,

F = E₁q₁

F = E₂q₂

Then

E₂q₂ = E₁q₁

E_2 = \frac{E_1q_1}{q_2}

where;

E₂ is the external electric field due to second test charge = ?

E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C

q₁ is the first test charge = 13 mC

q₂ is the second test charge = 23 mC

Substitute in these values in the equation above and calculate E₂.

E_2 = \frac{4*10^6*13}{23} = 2.26 *10^6 \ N/C

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.

However, the direction of the external field is still to the right.

8 0
3 years ago
Which sequence shows the chain of energy transfers that create surface currents on the ocean?
Papessa [141]

Answer:

The correct answer is A. The sun is the energy source of the surface currents in the ocean

6 0
2 years ago
Other questions:
  • Calculate the average speed of a gazelle that runs 140 meters in 5.0 seconds
    12·1 answer
  • .... is increasing the temperatures of earths oceans and atmosphere, leading to more intense storms of all types, including hurr
    6·1 answer
  • Insulators will:
    14·2 answers
  • Jerome plays middle linebacker for South's varsity football team. In a game against cross-town rival North, he delivered a hit t
    14·1 answer
  • Which of the following statements about electric field lines are true? (choose all that are true) a) They are only defined for p
    8·1 answer
  • A body accelerate uniformly from rest at 0.2m/s for one-fifth of a minute. Calculate the distance covered by the body.​
    12·1 answer
  • A common characteristic of mountains formed by two colliding continents is marine _______ rock. A. sedimentary B. limestone C. i
    7·1 answer
  • Explain the difference between the justice system laws and scientific laws
    7·1 answer
  • The towline exerts a force of p = 4 kn at the end of the 20-m-long crane boom. if u = 30, determine the placement x of the hook
    7·1 answer
  • How much work does a 60kg person do in walking up 5m of stairs
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!