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love history [14]
4 years ago
12

Suppose that while moving into an apartment you move a refrigerator into place by sliding it across the floor. The refrigerator w

eighs 895 N and the coefficient of static friction between the floor and the refrigerator is 0.400. What is the least force you could apply to the refrigerator to cause it to move?
Physics
1 answer:
sweet-ann [11.9K]4 years ago
4 0

Answer:

358 N

Explanation:

F=\mu N where F is the force, \mu is the coefficient of static friction between the floor and the refrigerator and N is the weight

Normally, N=mg hence F=\mu mg where m is the mass of object and g is the acceleration due to gravity

In this case, N is given as 895 N and the coefficient of static friction between the floor and the refrigerator is 0.400 hence substituting them in the formula we obtain

F=\mu N= 0.4\times 895 N= 358 N

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An elephant produces a 10Hz sound wave. Assuming the speed of sound in air is 344/s, determine the wavelength of this infrasonic
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34.5 m

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Given data : An elephant produces 10 Hz sound wave. Assuming the speed of sound in air is 345 m/s. To find : What is the wavelength of sound ? Answer : The wavelength of the sound is 34.5 m.

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2 years ago
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One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe
Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

\mu = \frac{m}{l}

\mu = \frac{8.79*10^{-3}}{70*10^{-2}}

\mu = 0.01255kg/m

The expression for the wavelength of the standing wave for the second overtone is

\lambda = \frac{2}{3} l

Replacing we have

\lambda = \frac{2}{3} (70*10^{-2})

\lambda = 0.466m

The frequency of the sound wave is

f_s = \frac{v}{\lambda_s}

f_s = \frac{344}{0.768}

f_s = 448Hz

Now the velocity of the wave would be

v = f_s \lambda

v = (448)(0.466)

v = 208.768m/s

The expression that relates the velocity of the wave, tension on the string and linear mass density is

v = \sqrt{\frac{T}{\mu}}

v^2 = \frac{T}{\mu}

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T = (0.01255kg/m)(208.768m/s)^2

T = 547N

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the n^{th} harmonic frequency is

f_n = nf_1

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

n=3

Then,

f_3 = 3f_1

Rearranging to find the fundamental frequency

f_1 = \frac{f_3}{3}

f_1 = \frac{448Hz}{3}

f_1 = 149.9Hz

7 0
3 years ago
ifif it takes 1-minute for 45 c of charge to pass a point in an electric circuit what is the current through the circuit?​
Rudiy27

Answer:

45C in a minute is

45/60 C in a second

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Explanation:

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3 years ago
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