Answer:
the third one is incorrect
Explanation:
10 x 10³= 10^1 x 10^3 = 10^4
Knowing the initial velocity and angle, the horizontal range formula is given by R= V^2sin(2teta) / g, so we can get
sin(2teta)=Rg/V^2
sin(2teta)= (180 x 9.8)/ 80^2= 0.27, sin(2teta)=0.27, 2teta=arcsin(0.27)=15.66, so teta=15.66/2
teta=7.83°
Answer:
a.241.08 m/s b. 196 Hz c. 392 Hz
Explanation:
a. Determine the speed of waves within the wire.
The frequency of oscillation of the wave in the string, f = nv/2L where n = harmonic number, v = speed of wave in string, L = length of string = 1.23 m.
Since f = 588 Hz which is the 6 th harmonic, n = 6. So, making v subject of the formula, we have
v = 2Lf/n
substituting the values of the variables into v. we have
v = 2 × 1.23 m × 588Hz/6
v = 241.08 m/s
b. Determine the frequency at which the wire will vibrate with the first harmonic wave pattern.
The first harmonic is obtained from f when n = 1,
So, f = v/2L = 241.08 m/s ÷ 1.23m = 196 Hz
c. Determine the frequency at which the wire will vibrate with the second harmonic wave pattern.
The second harmonic f' = 2f = 2 × 196 Hz = 392 Hz
Answer: Electrostatic force of attraction
Explanation: Electrostatic force of attraction is the force of attraction or repulsion between two electrically charged particles at rest. Like charges repel and unlike charges attract each other.
