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shutvik [7]
3 years ago
13

Describe the basic internal structure of Mercury.

Physics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

has a radius of 2439 km (1524 mi), and the metallic iron-nickel core is believed to make up about 75% of this distance. Measurements of the planet's magnetic field made by Mariner 10 as it flew by the planet indicates that this core is likely to be hot and fluid.

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Which one A or B Help Fast Now
irga5000 [103]

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the answer is b because it does not show evidence

3 0
3 years ago
Read 2 more answers
How can humidity be used to predict if it is going to rain?
postnew [5]
1. Humidity cannot be used to predict rain.
2. I'm pretty sure it's weather but I'm not 100% sure. Maybe like 89% sure.

3. Tempurature doesn't affect humidity.

4. Not sure but I think its the 3rd one
3 0
3 years ago
calculate the mass of potassium chlorate (kcio3) required to obtain 10g of oxygen in the following reaction:kclO3-kcl+O2​
igor_vitrenko [27]

First, balance the reaction:

_ KClO₃   ==>   _ KCl + _ O₂

As is, there are 3 O's on the left and 2 O's on the right, so there needs to be a 2:3 ratio of KClO₃ to O₂. Then there are 2 K's and 2 Cl's among the reactants, so we have a 1:1 ratio of KClO₃ to KCl :

2 KClO₃   ==>   2 KCl + 3 O₂

Since we start with a known quantity of O₂, let's divide each coefficient by 3.

2/3 KClO₃   ==>   2/3 KCl + O₂

Next, look up the molar masses of each element involved:

• K: 39.0983 g/mol

• Cl: 35.453 g/mol

• O: 15.999 g/mol

Convert 10 g of O₂ to moles:

(10 g) / (31.998 g/mol) ≈ 0.31252 mol

The balanced reaction shows that we need 2/3 mol KClO₃ for every mole of O₂. So to produce 10 g of O₂, we need

(2/3 (mol KClO₃)/(mol O₂)) × (0.31252 mol O₂) ≈ 0.20835 mol KClO₃

KClO₃ has a total molar mass of about 122.549 g/mol. Then the reaction requires a mass of

(0.20835 mol) × (122.549 g/mol) ≈ 25.532 g

of KClO₃.

7 0
2 years ago
A 4-kg block is connected by means of a massless rope to a 2-kg block as shown in the figure. Complete the following statement:
Vinvika [58]
Less than 0.5, but greater than 0
8 0
3 years ago
A four-wheel-drive vehicle is transporting an injured hiker to the hospital from a point that is 30 km from the nearest point on
zepelin [54]

Answer:

D=200\ km

Explanation:

distance on terrain, d_t=30\ km

  • distance on the road, d_r=70\ km
  • speed on terrain, v_t=30\ km.hr^{-1}
  • speed  on road, v_r=130\ km.hr^{-1}

<u>time taken on the terrain,</u>

t_t=\frac{d_t}{v_t}

t_t=\frac{30}{30}

t_t=1\ hr

<u>time taken to cover the distance on the road:</u>

t_r=\frac{d_r}{v_r}

t_r=\frac{70}{130}

t_r=\frac{7}{13}\ hr

<u>Now the distance covered on terrain in the total time:</u>

D= v_r\times (t_r+t_t)

D= 130\times (\frac{7}{13}+1)

D=130\times \frac{20}{13}\

D=200\ km

<em>is the distance the vehicle must target on the road to minimize the time taken in going off the road.</em>

3 0
3 years ago
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