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bearhunter [10]
3 years ago
10

The formation of nitrogen dioxide and oxygen,

Chemistry
1 answer:
kvasek [131]3 years ago
7 0

Answer:

The rate of reaction changes by a factor 6.

Explanation:

Given the reaction is first order.

Let us assume the initial concentration of NO is A and the initial concentration of O_3 is B.

So, we can write the rate of the reaction as

R=k[A][B]

Where,

R is the rate of reaction. And k is the rate constant.

Also, the initial concentration of NO has been increased by 0.5, and the initial concentration of  O_3 was increased by factor 4.

So, we have

R'=k[1.5A][4B]\\R'=6k[A][B]\\R'=6R

We can see the rate of reaction changes by a factor 6.

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2 years ago
. In a titration, a 25.0 mL sample of 0.150 M HCl is neutralized with 44.45 mL of Ba(OH)2. a. Write the balanced molecular equat
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Answer:

Equation of reaction:

a) 2HCl + Ba(OH)2 ==> CaCl2 + 2H2O

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Using titration equation

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 2

NB is the number of mole of base = 1

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CB is the molarity of base = to be calculated

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VB is the volume of base = 44.45mL

Substituting

0.15×25/CB×44.45 = 2/1

Therefore CB =0.15×25×1/44.45×2

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Answer:

if electrons are shared unequally between bonded atoms

Explanation:

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The charge of the electric dipoles is less than a full unit charge, so they are considered partial charges and are called delta plus (δ +) and delta minus (δ-).

Because positive and negative charges are separated at the bond, molecules with polar covalent bonds interact with the dipoles of other molecules. This produces intermolecular dipole-dipole forces between the molecules.

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3 years ago
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