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fredd [130]
3 years ago
5

Calculate 28.1g of silicon to moles

Chemistry
1 answer:
saul85 [17]3 years ago
5 0

Answer:

2.53•10^23 atoms

Explanation:

23 is the exponent btw

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Instantaneous speed because that is the speed in which the object (the car) is at in a given moment.
4 0
3 years ago
A 7.85 × 10-5 mol sample of copper-61 emits 1.47 × 1019 positrons in 90.0 minutes. what is the decay constant for copper-61
Lera25 [3.4K]


4.14x10^-3 per minute   
 First, calculate how many atoms of Cu-61 we initially started with by
multiplying the number of moles by Avogadro's number. 

 7.85x10^-5 * 6.0221409x10^23 = 4.7273806065x10^19   
 Now calculate how many atoms are left after 90.0 minutes by subtracting the
number of decays (as indicated by the positron emission) from the original
count. 
 4.7273806065x10^19 - 1.47x10^19 = 3.2573806065x10^19   
 Determine the percentage of Cu-61 left. 
 3.2573806065x10^19/4.7273806065x10^19 = 0.6890455577   
 The formula for decay is: 
 N = N0 e^(-λt) 
 where 
 N = amount left after time t 
 N0 = amount starting with at time 0 
 Î» = decay constant 
 t = time   
 Solving for λ: 
 N = N0 e^(-λt) 
 N/N0 = e^(-λt) 
 ln(N/N0) = -λt 
 -ln(N/N0)/t = λ   
 Now substitute the known values and solve: 
 -ln(N/N0)/t = λ 
 -ln(0.6890455577)/90m = λ 
 0.372447889/90m = λ 
 0.372447889/90m = λ 
 0.00413830987 1/m = λ   
 Rounding to 3 significant figures gives 4.14x10^-3 per minute as the decay
constant.
5 0
3 years ago
Nitrogen gas consists of _____.
Anni [7]
Nitrogen gas consists of a diatomic nitrogen atom. So, the correct answer is B.
8 0
3 years ago
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7 0
3 years ago
1) A common experiment to determine the relative reactivity of metallic elements is to place a pure sample of one metal into an
Annette [7]

Answer: Zn(s)+CuSO_4(aq)\rightarrow ZnSO_4+Cu

Explanation:-

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

As zinc is more reactive than copper, it could easily displace copper from its aqueous solution and thus leads to formation of zinc (II) sulfate and pure copper.

The chemical reaction can be represented as :

Zn(s)+CuSO_4(aq)\rightarrow ZnSO_4+Cu

The phases are represented as (s) for solid sate, (l) for liquid state, (g) for gaseous state and (aq) for aqueous state.

7 0
4 years ago
Read 2 more answers
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