the answer is b it is composed of protons and neutrons.
hope this helped
Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄ 
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Hey there!
27 tells us the sum of protons and neutrons is 27.
Al tells us we have 13 protons.
3+ tells us that there are 3 less electrons than protons.
13 + n = 27
neutrons = 14
13 - 3 = 10 electrons
27Al3+ has 13 protons, 14 neutrons, and 10 electrons.
Hope this helps!
Answer:
0.286 moles
Explanation:
i hope this is helpful for you