Answer:
32.7 kilograms of aluminium oxide will be produced.
Explanation:
![2 Al ( s ) + Fe_2O_3 ( s ) +heat\rightarrow Al_2O_3 ( s ) + 2 Fe ( l )](https://tex.z-dn.net/?f=2%20Al%20%28%20s%20%29%20%2B%20Fe_2O_3%20%28%20s%20%29%20%2Bheat%5Crightarrow%20Al_2O_3%20%28%20s%20%29%20%2B%202%20Fe%20%28%20l%20%29)
Mass of aluminum = 17.3 kg = 17300 g (1 kg = 1000 g )
Moles of aluminium = ![\frac{17300 g}{27 g/mol}=640.74 mol](https://tex.z-dn.net/?f=%5Cfrac%7B17300%20g%7D%7B27%20g%2Fmol%7D%3D640.74%20mol)
According to reaction, 2 moles of aluminum gives 1 mole of aluminum oxide,then 640.74 moles of aluminum will give:
of aluminum oxide
Mass of 320.37 moles of aluminum oxides:
320.37 mol × 102 g/mol = 32,677.74 g = 32.67774 kg ≈ 32.7 kg
32.7 kilograms of aluminium oxide will be produced.
Answer:
0.131 mol
Explanation:
To convert grams to moles, you need to use the molar mass. The molar mass is the mass number. You can find this on the periodic table. The molar mass of sodium is 22.990 g/mol.
(3.02 g)/(22.990 g/mol) = 0.131 mol
Answer:
Various limitations of Mendeleev's periodic table are:-
Position of hydrogen - he couldn't assign a correct position to hydrogen as it showed properties of both alkali and halogens .
Position of isotopes - he considered that the properties of elements are a function of their atomic masses. Hence isotopes of a same element couldn't be placed.
In the d-block , elements with lower atomic number were placed before higher atomic number.
Explanation: