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weqwewe [10]
2 years ago
5

During physical activity of moderate intensity, your heart will beat at a percentage of its maximum rate. What is the target hea

rt rate for moderate-intensity activity?
Physics
1 answer:
Phoenix [80]2 years ago
8 0
The target heart rate for moderate-intensity activity is 80%
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An object exhibits SHM with an angular frequency w = 4.0 s-1 and is released from its maximum displacement of A = 0.50 m at t =
vivado [14]

Explanation:

It is given that,

Angular frequency, \omega=4\ s^{-1}

Maximum displacement, A = 0.5 m at t = 0 s

We need to find the time at which it reaches its maximum speed. Firstly, we will find the maximum velocity of the object that is exhibiting SHM.

v_{max}=A\times \omega

v_{max}=0.5\times 4

v_{max}=2\ m/s............(1)

Acceleration of the object, a=\omega^2A

a=4^2\times 0.5

a=8\ m/s^2...............(2)

Using first equation of motion we can calculate the time taken to reach maximum speed.

v=u+at

t=\dfrac{v-u}{a}

t=\dfrac{2-0}{8}

t = 0.25 s

So, the object will take 0.25 seconds to reach its maximum speed. Hence, this is the required solution.

4 0
3 years ago
You run from your friends house that is 1k away. You then walk home. What distance did you travel?
kolezko [41]

Would would have moved a total distance of 2k, because walking is a slower speed does not change distance

6 0
3 years ago
An electromagnetic wave moves through electric and magnetic fields. How might the movement of the wave be described?
Elenna [48]

A. The vibrations of the fields are perpendicular to the direction in which the wave moves.

7 0
3 years ago
Isabella drops a pen off her balcony by accident while celebrating the successful completion of a physics problem.
Studentka2010 [4]

Answer:

2 seconds

Explanation:

v = at + v₀

19.62 m/s = (9.81 m/s²) t + 0 m/s

t = 2 s

6 0
3 years ago
Read 2 more answers
The magnetic field at the centre of a toroid is 2.2-mT. If the toroid carries a current of 9.6 A and has 6.000 turns, what is th
ziro4ka [17]

Answer:

Radius, r = 0.00523 meters

Explanation:

It is given that,

Magnetic field, B=2\ mT=2.2\times 10^{-3}\ T

Current in the toroid, I = 9.6 A

Number of turns, N = 6

We need to find the radius of the toroid. The magnetic field at the center of the toroid is given by :                  

B=\dfrac{\mu_oNI}{2\pi r}

r=\dfrac{\mu_oNI}{2\pi B}  

r=\dfrac{4\pi \times 10^{-7}\times 6\times 9.6}{2.2\pi \times 2\times 10^{-3}}  

r = 0.00523 m

or

r=5.23\times 10^{-3}\ m

So, the radius of the toroid is 0.00523 meters. Hence, this is the required solution.

7 0
2 years ago
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