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ra1l [238]
3 years ago
7

Although the vocal tract is quite complicated, we can make a simple model of it as an open-closed tube extending from the openin

g of the mouth to the diaphragm, the large muscle separating the abdomen and the chest cavity. What is the length of this tube if its fundamental frequency equals a typical speech frequency of 200 Hz?
Physics
1 answer:
andriy [413]3 years ago
3 0

Answer: 0.429m

Explanation: fundamental frequency is 200 Hz and the speed of sound in air is 343 m/s.

Recall that v = fλ

Where v = speed of sound = 343 m/s

f = frequency of sound = 200 Hz

λ = wavelength of sound =?

By substituting the parameters, we have that

343 = 200 × λ

λ = 343/ 200

λ = 1.715m.

Since the vocal tract is assumed to be an open-closed tube, the relationship between the length of air and wavelength at fundamental frequency is given below as

L = λ/ 4

But λ = 1.715m

L = 1.715/4

L = 0.429m

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