The prefix for the number 1.5x10^11 m is hundred-giga...
A quantity of meters can't be expressed in units of mass. If it could, then you'd be able to calculate how many kilograms you have to walk or ride to get to school.
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Just took a test in science with this!
Answer:
the maximum height reached by the object from where it was launched is 0.4591 m
Explanation:
initial speed of the object, u= 3 m/s
The velocity at the maximum height will always be 0.
Therefore, final velocity, v= 0 m/s
Using the Newton's equation of motion,
v^2 - u^2 = 2*g*h(max)
0 - u^2= 2*g*h(max)
h(max) = -u^2 /2* g
where g is the gravitational acceleration.
g= - 9.8 m/s^2
substituting the values in equation,
h(max)= - (3*3) / 2*(-9.8)
h(max) = 0.4591 m
the maximum height reached by the object from where it was launched is 0.4591 m
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Answer:
Net force would be zero
Explanation:
It's still receiving a gravitational force of almost 500 Newtons downward, but because it has reached terminal velocity, that means it's also receiving an opposite and roughly equal force due to friction with the air. The two balance out for a total of zero.