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Irina-Kira [14]
4 years ago
9

An object that has negative acceleration is definitely doing what?

Physics
1 answer:
krek1111 [17]4 years ago
3 0

If an object is consist of a negative acceleration or composed of it, it is likely engaging of having to accelerate in a certain direction in which the direction is heading towards the opposite of the direction that is stated and that is likely to be a positive direction.

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Suppose that John lives on a square block that is 180 yards per side, and in the evenings, he walks with his dog around the bloc
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_____ variables are manipulated by the experiments
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dependent variables

Explanation:

dependent varibeles are the thing you're measuring and independent variables are the thing you change in the exeriment to get a different dependent variable.

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4 years ago
All parts of the electromagnetic spectrum travel at a speed of 3 × 108 m/s when traveling through no medium. A "vacuum” means th
il63 [147K]

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3 years ago
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A 22-g bullet traveling 265 m/s penetrates a 1.9 kg block of wood and emerges going 125 m/s .
Usimov [2.4K]

The body moves at a velocity of 1.62m/s after the bullet emerges.

<h3>Given:</h3>

Mass of bullet, m_1 = 22g

                               = 0.022 kg

Mass of the block, m_2 = 1.9 kg

Velocity of bullet , v_1 = 265 m/s

v_2 = 0

According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.

After penetration;

v^{'}_1 =125 m/s

v^{'}_2=?

The formula for calculating the collision of a body is expressed as:

p = mv

m is the mass of the body

v is the velocity of the body

∴ Momentum before = Momentum after

Substitute the given parameters into the formula as shown:

   m_1v_1+ m_2v_2 = m_1v^{'}_1+ m_2v^{'}_2\\0.022* 265 + 0 = 0.022*125+1.9*v^{'}_2\\5.83 = 1.9 v^{'}_2\\v^{'}_2 = 1.62 m/s

Therefore, It moves with a velocity of 1.62 m/s.

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6 0
2 years ago
The escape speed from an object is v2 = 2GM/R, where M is the mass of the object, R is the object's starting radius, and G is th
Rom4ik [11]

Answer:

Approximate escape speed = 45.3 km/s

Explanation:

Escape speed

        v=\sqrt{\frac{2GM}{R}}

Here we have

   Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

   R = 1 AU = 1.496 × 10¹¹ m

   M = 2.3 × 10³⁰ kg

Substituting

    v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 2.3\times 10^{30}}{1.496\times 10^{11}}}=4.53\times 10^4m/s=45.3km/s

Approximate escape speed = 45.3 km/s

6 0
3 years ago
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