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1 year ago

Which compounds are bases in aqueous solution according to brønsted–lowry theory?.

Chemistry

1 answer:

Fittoniya [83]1 year ago

3 0

Ammonia compounds are bases in aqueous solution according to brønsted–lowry theory.

<h3>What are bases?</h3>

A base is a substance that can neutralize the acid by reacting with hydrogen ions.

Ammonia compounds are based on an aqueous solution according to brønsted–lowry theory because the water molecule donates a hydrogen ion to the ammonia, it is the Brønsted-Lowry acid, while the ammonia molecule which accepts the hydrogen ion is the Brønsted-Lowry base. Thus, ammonia acts as a base in both the Arrhenius sense and the Brønsted-Lowry sense.

Hence, ammonia compounds are based on an aqueous solution according to brønsted–lowry theory.

Learn more about the bases here:

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A sample of copper metal has a mass of 848 grams. How many moles of copper are in the sample? 13.34 mol Cu, 13.3 mol Cu, 12.9 mo

ANTONII [103]

Answer:

$mol_{Cu}=13.34molCu$

Explanation:

Hello,

In this case, as the atomic mass of coppe is 63.546 g/mol, with the given mass with can compute the moles as shown below:

$mol_{Cu}=848gCu*\frac{1molCu}{63.546 gCu} \\\\mol_{Cu}=13.34molCu$

Best regards.

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3 years ago

13.50 grams of Pb(NO3)4 are dissolved in enough water to make 250 mL of solution. What is the molar its of the resulting solutio

likoan [24]

Data:
M (molarity) = ? (M or Mol/L)
m (mass) = 13.50 g
V (volume) = 250 mL → 0.25 L
MM (Molar Mass) of Lead(IV) Nitrate $Pb(NO_3)_4$
Pb = 1*207 = 207 amu
N = (1*14)*4 = 14*4 = 56 amu
O = (3*16)*4 = 48*4 = 192 amu
------------------------------------
MM of $Pb(NO_3)_4$ = 207+56+192 = 455 g/mol

Formula:
$M = \frac{m}{MM*V}$

Solving:
$M = \frac{m}{MM*V}$
$M = \frac{13.50}{455*0.25}$
$M = \frac{13.50}{113.75}$
$M = 0.118681318...\:\:\to\:\:\boxed{\boxed{M \approx 0.119\:Mol/L}}\end{array}}\qquad\quad\checkmark$

Answer:
<span>B. 0.119 M</span>

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lilavasa [31]

Answer:

24 atoms makes altogether a molecule of glucose

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Incomplete question. Full question reads;

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