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dybincka [34]
3 years ago
10

Pete’s Painting Company will charge a one-time fee of $60 for labor and $20 for each room painted. Carla’s Creative Colors will

charge $40 a room but only $20 to hire workers. Write a function rule for Pete’s Painting Company in function notation. Write a function rule for Carla’s Creative Colors in function notation.
Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

Pete's: f(x) = 20x + 60

Carla's: f(x) = 40x + 20

Step-by-step explanation:

Let's assume that x is the amount of rooms painted, and f(x)

For Pete's Painting Company, they charge a flat fee of $60, so we will have a constant of 60.

They also charge 20$ per room, meaning that we will multiply 20 by x, the amount of rooms painted.

This gets us the function f(x) = 20x + 60

For Carla's Creative Colors, they charge 20$ to hire the workers, meaning this will be our constant.

They also charge $40 a room, meaning we will multiply 40 by x, the amount of rooms painted.

So the function is  f(x) = 40x + 20.

Hope this helped!

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Inimum value of y=4x^2+4x-35?
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Hello there!

There are two ways to find the minimum value of this function, but before I show you how, I am going to teach you a little bit about minimum value.

The minimum value on a parabola is the vertex or turning point. This means that the slope of the tangent line is horizontal, having a slope of 0.

The algebraic way to find the minimum or maximum value on a parabola is to use the formula -b/2a. Let's do it...

y=4x^2+4x-35
where a=4, b=4, and c=-35
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Now let me show you the other way...
Take the derivative of
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And set it equal to 0...
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We got the same answer. Now that we know x=-1/2, plug this into the original equation to find y.
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8 0
3 years ago
A: 2.86<br> B: 2.75<br> C: 2.95<br> D: 1.17
zhuklara [117]
No doubt your text advises how to arrive at a best-fit exponential model. The two graphing calculators I used gave different answers. The first one modeled the function as
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The second calculator, a TI-84 work-alike, modeled the function as
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Using the first and last data points only, the model is
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Using yet another calculator to do linear regression on the log of y, the function is modeled by
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So, the technology I used gives a couple of reasons to choose
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and a couple of reasons to choose
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Of the models shown here, the ones with the lowest mean absolute deviation and the least squared error were the ones that produced the highest values of y for x=7, suggesting 2.95 is the best choice.


It would be advisable to use the procedure described in your text.

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