Answer:
the first overtone is 200 Hz
Explanation:
The computation of the first overtone would be given below:
The following formula should be applied
n_1 = n_3 ÷ 3
= 300 ÷ 3
= 100 Hz
Now n_2 is
= 2 × 100
= 200 Hz.
Hence, the first overtone is 200 Hz
we simply applied the above formula and the same would be relevant
The cost of boiling 500cm3 of water using the 3kW kettle is 1.35 P.
<h3>
Cost of electricity for 3 kW kettle</h3>
The cost is calculated as follows;
1 unit = 9p /kWh
Total energy consumed by 3 kW kettle, E = P x t
where;
- P is power (kW)
- t is time in (hr)
E = 3 kW x (3 mins/60 mins/hr)
E = 0.15 kWh
Energy cost = 9 p/kWh x 0.15 kWh = 1.35 P
Thus, the cost of boiling 500cm3 of water using the 3kW kettle is 1.35 P.
Learn more about energy cost here: brainly.com/question/13795167
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Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.
Answer:
Triton orbits Neptune in what is known as a retrograde orbit. This means that it orbits Neptune a direction opposite the planet's rotation. ... Others think that Triton may have been formed elsewhere and then captured by Neptune's gravity.
Explanation:
i hope it's help......
Answer:
Explanation:
One of the easiest ways to work with vectors is to use their components
a) To find the magnitude let's use the Pythagorean theorem
A² = Ax² + Ay² + Az²
A = √ 3² + 4² + (-5)² = √ 50
A = 7.07
B = √ Bx² + By² + Bz²
B = √ (-2)² + 0 + 6² = √ 40
B = 6.32
b) to find these angles the most practical use the concept of cosine directors with the formulas
Vector A
cos α = X / A
cos β = y / A
cos γ = z / A
cos α = 3 / 7.07
α = cos⁻¹ 0.424
α = 64.9º
cos β = 4 / 7.07
β = cos⁻¹ 0.5658
β = 55.5º
Cos γ = -5 / 7.07
γ=Cos⁻¹ (-0.7079)
γ= 135º
Vector B
cos α = X / B
cos β = y / B
cos γ = z / B
cos α = 0
α = 90º
cos β = -2 / 6.32
β = 108.4º
cos γ = 6 / 6.32
γ = 18.3º
c) find A + B
R = A + B = (3 + 0) i ^ + (4-2) j ^ + (-5 +6) k ^
R = 3 i ^ + 2j ^ + 1 k ^
d) to find the angles we use the scalar product
cos θ = A.B / | A | | B |
A.B = 0 i ^ -8 j ^ -30 k ^
Cos θ = [R (8 2 + 30 2)] / 7.07 6.32
Cos θ = 31.05 / 44.68
θ = 46º
e) find A-B
R = A-B = (3-0) i ^ + (4- (2)) j ^ + (-5 - 6) k ^
R = 3 i ^ + 6j ^ -11 k ^