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Marianna [84]
3 years ago
7

What are three things that the elements Magnesium, Calcium and Barium have in common?

Chemistry
1 answer:
Volgvan3 years ago
6 0

Answer:

1.They are all in the second group of the periodic table

2.They are an alkaline earth metal

3.They all have a shine to them

4.They are all highly reactive

5.They have a silver/white to them

6.They can all be found in the Earths crust

I'm not really sure of any others that they have in common and I thought to give extra so you could choose.

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60<br> х<br> 8<br> у<br> x=<br> 04<br> 09<br> O 16
vovikov84 [41]

Answer:

The answer is 16

Explanation:

It needs to be hald of the medium so devide the 2 numbers

7 0
3 years ago
Make an oblique drawing (page 9)
Olin [163]
Good luck folk :)!!!!!!!!
4 0
2 years ago
A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M Na
s344n2d4d5 [400]

Answer:

a: before equivalence point

b: equivalence point

c: before equivalence point

d: after the eqivalence point

e: before equivalence point

f:  after the eqivalence point

Explanation:

Balanced equation of reaction:

NaOH +HCl =NaCl +H2O;

Volume of HCl is fixed and it 100ml and concentration is 1.0M

N1 and N2 normality of HCl and NaOH respectively;

V1 and V2 volume of HCl and NaOH respectively;

we have given molarity but we need normality;

Normality=molarity \times n-factor

<em>but in case of NaOH and HCl n-factor is 1 for each.</em>

hence

normality=molarity;

At equivalence point:  N_1V_1=N_2V_2

Before equivalence point : N_1V_1>N_2V_2

After the equivalence point: N_1V_1

N_1V_1=100\times1=100

case a:  5.00 mL of 1.00 M NaOH

N_2V_2=5\times1=5

N_1V_1>N_2V_2 hence it is before equivalence point

case b: 100mL of 1.00 M NaOH

N_2V_2=100\times1=100

N_1V_1=N_2V_2 hence it is equivalence point

case c:  10.0 mL of 1.00 M NaOH

N_2V_2=10\times1=10

N_1V_1>N_2V_2 hence it is before equivalence point

case d: 150 mL of 1.00 M NaOH

N_2V_2=150\times1=150

N_1V_1 hence it is after the eqivalence point

case e: 50.0 mL of 1.00 M NaOH

N_2V_2=50\times1=50

N_1V_1>N_2V_2 hence it is before equivalence point

case f: 200 mL of 1.00 M NaOH

N_2V_2=200\times1=200

N_1V_1 hence it is after the eqivalence point

7 0
3 years ago
HELP!! An unknown solution has a pH reading of 8.4. Which statement is true about this solution?
yarga [219]

Answer:

D- a weak base

Explanation:

The ph scale goes from 1-10 a solution over 7ph is classified as basic. A solution thats 8.4 is only 1.4 over 7pH, making it a weak basic solution. An example of a strong base would be a solution with a pH of 9.2 (for example).

8 0
2 years ago
A liter of water has a mass of 1000 g. What is the density of water?
allsm [11]

Answer: D = 1g/ml

Explanation:

6 0
3 years ago
Read 2 more answers
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