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NISA [10]
3 years ago
10

a. A 65-cm-diameter cyclotron uses a 500 V oscillating potential difference between the dees. What is the maximum kinetic energy

of a proton if the magnetic field strength is 0.75 T? b. How many revolutions does the proton make before leaving the cyclotron?

Physics
1 answer:
Sati [7]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

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A rocket is launched from atop a 101 foot cliff with an initial velocity of 116 ft/s.
Katen [24]

Answer:

A. 16t2 -116t -101=0 B. 8.0s

Explanation:

Known parameters from the question:

Height of Cliff,h0 = 101ft

Velocity of rocket ,v= 116ft/s.

1.Substituting the above to the above formula we have;

h(t) = -16t2 + vt + h0

Since h(t) =0, it means the rocket is falling towards the ground, when it gets to the ground when it's at rest the height h(t) = 0m

{Note the rocket is launched from the height of the Cliff so that would be the initial height of the rocket,h0}

2.Substituting into h(t) = -16t2 + vt + h0

We have;

0 = -16t2 + 116t + 101=> 16t2 -116t -101=0

Using formula method for solving quadratic equation we have;

t = -(-116)+_√[(-116)^2 -( 4× 16 ×-101]/ (2× 16)

t = [116 +_(141.1382)]/32

t = (116 -141.1382)/32 or (116 +141.1382)/32

-0.786s or 8.036s

-0.8s or 8.0s to the nearest tenth.

Now time cannot be negative in real life situation hence the time is 8.0s

Note : the general equation of a quadratic equation with variable t is given below;

at2 + bt + c=0

Formula method for quadratic equation is :

t =( -b+_√[(b^2 -( 4× a×c)] ) / (2× a)

6 0
3 years ago
Two people are carrying a uniform wooden board that is 3.00 m long and weighs 160 N. If one person applies an upward force equal
Amanda [17]

Answer:

0.9 meters

Solution:

In these type of questions there are two equations:

First one is Force Balance and second one is Torque Balance.

<u>Force Balance</u>

First equation is generally used to know the magnitude of the force applied.

Since they have to lift wooden board in order to carry it, therefore they have to apply a counter force to overcome its weight, which is 160 N.

So the net force applied by the two men in upward direction is 160 N.

The force applied by person 1 (as in the figure attached) is 60 N and by person 2 is F N. So,

60 + F = 160

∴ F = 100 N

<u>Torque Balance</u>

(<em>Torque is nothing but a twisting force that tends to cause rotation.</em>

<em>To calculate torque multiply the force applied with the perpendicular distance between axis of rotation and line of application of force</em>)

The second equation is generally used to know the position of the force applied.

Since they are carrying wooden board in horizontal position, therefore there is no net torque on the wooden board.

To calculate torque first of all choose the axis of rotation. Here, there is no rotation so you can choose any axis of rotation which can help you to calculate the distance of application of force. Here the axis of rotation is chosen as the axis perpendicular to the wooden board passing through the center of it.

Since torque of two person are opposing each other as one is in clockwise direction and other one is in anticlockwise direction, therefore, if they are equal then the net torque will become zero. So,

60 \times 1.5 = F \times x

60 \times 1.5 = 100 \times x

90 = 100 \times x

x = \frac{90}{100}

x = 0.9 meters

<em>( NOTE: If you apply force in the same half side then the torque won't oppose each other rather it will support each other)</em>

3 0
3 years ago
Explain the microsoft word skills you are most confident in performing.<br><br>​
Sladkaya [172]
Yes this is not gonna work
4 0
3 years ago
In consideration of the above diagram, a projectile is launched at 45 with an initial horizontal velocity (V0x) of 3 m/s. Calcul
kumpel [21]

CFISD too huh? :D

also tryna get the answer

8 0
3 years ago
Which is a common source of experimental error?
kap26 [50]

Hello,

The option "framing a hypothesis without knowing for sure that it is correct" is the answer.

This is the most common mistake done by many scientists.

<em>By</em><em> Benjemin</em>

7 0
2 years ago
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