Explain the microsoft word skills you are most confident in performing.<br><br>

A=(v – u)/t<br><br> i. V as subject<br> ii. U as subject<br> iii. T as subject

Norma-Jean [14]

Answer:

i.

$a = \frac{(v - u)}{t} \\ v - u = at \\ v = at + u$

ii.

$a = \frac{(v - u)}{t} \\ v - u = at \\ u = v - at$

iii.

$a = \frac{(v - u)}{t} \\ ta = v - u \\ t = \frac{(v - u)}{a}$

I hope I helped you^_^

8 0

3 years ago

an object starts at rest and accelerates until it is moving at 247 km/h. if it takes 1.7minutes for this change to occur what is

d1i1m1o1n [39]

The average acceleration in 0.67 m/s^2.

The average acceleration is calculated as change in velocity/time

a=(247*5/18)/(1.7*60)

=68.61/102=0.67 m/s^2

Therefor the average acceleration of the object is 0.67 m/s^2

5 0

3 years ago

ASK YOUR TEACHER A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 51.5-gram mass is attach

Simora [160]

Answer:

0.114 kg or 114 g

Explanation:

From the diagram attaches,

Taking the moment about the fulcrum,

sum of clockwise moment = sum of anticlockwise moment.

Wd = W'd'

Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.

make W' the subject of the equation

W' = Wd/d'................ Equation 1

Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm

Substitute these values into equation 1

W' = 0.5047(23.2)/10.5

W' = 1.115 N.

But,

m' = W'/g

m' = 1.115/9.8

m' = 0.114 kg

m' = 114 g

6 0

3 years ago

HELP PLEASE AND HURRRRRY

kykrilka [37]

Answer:

the path the object follows is called its trajectory so A. trajectory

6 0

3 years ago

Starting from rest, you pushed a 10.0 kg lawnmower a distance of 25 meters by applying a force of 75 N at an angle 35 degrees be

irga5000 [103]

The lawn mower is moving with a velocity of 17.53 m/s

<h3>Definition of Energy and Work </h3>

Energy is the ability to do work while Work is defined as the product of force and distance moved in the direction of the force. Both work and energy are measured in Joule (J)

Work = Force (F) × distance (d) = FdCosθ

With the above formula, we can obtain the energy used in pushing the lawn mower as illustrated below

From the question given above, the following data were obtained:

•Force (F) = 75 N

•Distance (d) = 25 m

•Angle (θ) = 35°

•Energy (E) =?

E = FdCosθ

E = 75 × 25 × Cos 35

E = 1535.91 J

<h3>Definition and Determination of the velocity</h3>

Velocity is the rate of change of displacement with time.

Velocity and energy are related according to the following equation:

E = ½ × mass (m) × square velocity (v²)

E = ½mv²

With the above formula, we can obtain the velocity of the lawn mower as follow

•Mass (m) = 10 Kg

•Energy (E) = 1535.91 J

•Velocity (v) =?

E = ½mv²

1535.91 = ½ × 10 × v²

1535.91 = 5 × v²

Divide both side by 5

v² = 1535.91 / 5

Take the square root of both side

v = √(1535.91 / 5)

v = 17.53 m/s

Thus, the lawn mower is moving with a velocity of 17.53 m/s

<h3 />

Learn more about energy:
brainly.com/question/10703928

4 0

2 years ago

Explain the microsoft word skills you are most confident in performing.​

Explain the microsoft word skills you are most confident in performing.