The only information you would need to decide if the can will float is the density of the can, which requires knowing the mass and volume. If the density of the can is less than one, the can will float. if it is greater than one, it will not float, as water's density is one.
Answer:
33.33j+6.67i km/hr
Explanation:
From the law of conservation of momentum,
Applying,
mu+m'u' = V(m+m')............... Equation 1
Where m = mass of the truck, m' = mass of the car, u = initial velocity of the truck, u' = initial velocity of the car, V = Final velocity.
Note: let j represent the north, and i represent the east
From the question,
Given: m = 1500 kg, u = 60j, m' = 1200 kg, u' = 15i
Substitute these values into equation 1
1500*60j+1200*15i = V(1500+1200)
90000j+18000i = 2700V
V = (90000j+18000i)/2700
V = 33.33j+6.67i km/hr
Answer:
A) 2
Explanation:
Given;
magnetic field of the coil, B = 1.6 T
frequency of the coil, f = 75 Hz
maximum emf developed in the coil, E = 56.9 V
area of the coil, A = 0.15 m x 0.25 m = 0.0375 m²
The maximum emf in the coil is given by;
E = NBAω
Where;
N is the number of turns
ω is the angular velocity = 2πf = 2 x 3.142 x 75 = 471.3 rad/s
N = E / BAω
N = 56.9 / (1.6 x 0.0375 x 471.3)
N = 2 turns
Therefore, the value of N is 2
A) 2
Answer:
R₂ = 3.31 m
Explanation:
For this exercise let's use trigonometry. Let's see the angle of the full moon
θ = x / R
Where x is the diameter of the moon and R the distance from the Earth to the Moon, the angle is measured in radians
x = 2 R
x = 2 1.74 10⁶
x = 3.48 10⁶ m
The distance is
R = 3.84 10⁸ m
Let's look for the supported angle
θ = 3.48 10⁶ / 3.84 10⁸
θ = 9.06 10⁻³ rad
For the coin to cover the moon it must have the same angle, let's look for the different
θ = x₂ / R₂
x₂ = 3 cm = 0.03 m
R₂ = x2 / θ
R₂ = 0.03 / 9.06 10⁻³
R₂ = 3.31 m
This distance in much greater than the arm length