1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tamiku [17]
1 year ago
7

What two vertical forces act on a falling leaf?(1 point)

Physics
1 answer:
Sloan [31]1 year ago
5 0

Option C. Weight, Friction are the vertical forces that act on the leaf falling.

<h3>What are vertical forces?</h3>

These are forces that act in the vertical plane, which is perpendicular to the ground. There are at least two vertical forces acting. Gravitational force is provided by the earth and always acts downwards.

The weight, W (force) acting on the leaf is as a result of the product of the mass(m) of the leaf and the acceleration due to gravity (g).

Mathematically; W = mg

Friction in the form of air resistance also try to stop or reduce this acceleration due to gravity (g) on the falling leaf and it acts upwards.

In conclusion, Weight and Friction (air resistance) are the two vertical forces acting on a falling leaf.

Learn more about forces: brainly.com/question/12970081

#SPJ1

You might be interested in
Two objects with a mass of 10,000-kg each and a distance of 1 meter between them.
Fofino [41]

Answer:

d) What is the force if we doubled both the masses AND we doubled the distance

4 0
2 years ago
Consider one such cell where the magnitude of the potential difference is 65 mV, and the inner surface of the membrane is at a h
Gelneren [198K]

Answer: W = 1.04.10^{-20} J

Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.

The work to transport an ion from a lower potential side to a higher potential side is calculated by

W=q.\Delta V

q is charge;

ΔV is the potential difference;

Potassium ion has +1 charge, which means:

p = 1.6.10^{-19} C

To determine work in joules, potential has to be in Volts, so:

\Delta V=65.10^{-3}V

Then, work is

W=1.6.10^{-19}.65.10^{-3}

W=1.04.10^{-20}

To move a potassium ion from the exterior to the interior of the cell, it is required W=1.04.10^{-20}J of energy.

8 0
3 years ago
Interdependence between plants and animals<br>​
Rama09 [41]

Answer:

plants depend on animals for CO2 (to use during photosynthesis) while animals depend on plants for food (consumation)

Explanation:

5 0
3 years ago
the cross section area of a hole is 725cm^2. Given that the area of a circle is A=3.14r^2 , find the radius of the hole.
asambeis [7]
The\ area\ of\ a\ circle\ =  \pi r^2 \\ 725\ cm^2 =  3.14r^2 \\&#10;230.57 cm^2 = r^2 \\ \sqrt{230.57\ cm^2} = r \\ \boxed{r = 15.18\  cm}
7 0
3 years ago
You toss a rock up vertically at an initial speed of 39 feet per second and release it at an initial height of 6 feet. The rock
3241004551 [841]

Answer:

2.583 s, 29.77 ft and 1.219 s

Explanation:

Using equation of motion and taken the motion upward as positive, also a = g ( acceleration due to gravity) = - 32 fts⁻², V= 39 fts⁻¹ V₁ is final velocity, y is the distance in ft from the ground

H = 6 ft, the height from which it is tossed

V₁ = V + gt = V - gt

at maximum height the body came to rest momentarily V₁ = 0

0 = V - gt

-V = -gt

- 39 / -32 = t

t time to reach maximum height = 1.219 s

To Maximum height reached can be calculated with the formula

V₁² = V² + 2g( y - H) where H is the initial height reached by the tossed rock

where V₁ is the final velocity at maximum height which = 0

0 = V² - 2g(y-H) where y is the distance traveled from the ground

-V² = -2g(y-H)

₋V² / -2g = y-H

(V²/2g) + H = y in ft

(39² / (2 × 32)) + 6

y = 29.77 ft

The total time it will be in air can be calculated with the formula below

y = H + Vt - 0.5gt² from y-H = ut + 0.5at²

0.5gt² - Vt - H = 0 since the body returned to the ground ( y = 0)

0.5gt² - Vt - H = 0

using quadratic formula

- (-V)² ± √ ((-V²) - 4 × 0.5g × -H) / (2 × 0.5 × g)

(V ± √ (V² + 2gH)) ÷ g

substitute the values into the expression

t = (39 + √(39² + (2×-32× 6)))/ 32 or (39 - √ (39² + (2 × -32×6))/ 32

t = (39 + √(1521 +384))/32 = (39 + √1905) / 32  = 2.583 s

t = (39 - √1905) / 32 =  -0.15 s

The will remain in air (V ± √ (V² + 2gH)) / g seconds. It will reach a maximum height of (V²/2g) + H feet after V/g seconds

8 0
3 years ago
Other questions:
  • When did diesel locomotives replace steam locomotives?
    11·1 answer
  • A horse running at 3 m/s speeds up with a constant acceleration of 5 m/s2. How fast is the
    15·1 answer
  • When he sees teachers encouraging other children to wait in the cafeteria until the first bell rings, Ian follows them. What typ
    11·2 answers
  • The mass number of an atom is equal to ______.
    10·2 answers
  • Density is ____ per unit volume.
    5·2 answers
  • An orange of mass 40g falls freely from a tree to the ground through a distance of 2.5m. Calculate the velocity just before it h
    15·1 answer
  • While researching scuba diving, Pablo reads how hot a tank should get while being filled with air. Which law best explains why t
    14·2 answers
  • A mixture of iron and sulfur can be separated by
    7·2 answers
  • ASAP PLEASE HELP!<br> What is nuclear potential energy?
    8·2 answers
  • In what section of the EM spectrum can we find visible light?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!