Answer:
0.167m/s
Explanation:
According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.
Given momentum = Maas × velocity.
Momentum of glider A = 1kg×1m/s
Momentum of glider = 1kgm/s
Momentum of glider B = 5kg × 0m/s
The initial velocity of glider B is zero since it is at rest.
Momentum of glider B = 0kgm/s
Momentum of the bodies after collision = (mA+mB)v where;
mA and mB are the masses of the gliders
v is their common velocity after collision.
Momentum = (1+5)v
Momentum after collision = 6v
According to the law of conservation of momentum;
1kgm/s + 0kgm/s = 6v
1 =6v
V =1/6m/s
Their speed after collision will be 0.167m/s
Answer:
The velocity of wind with respect to cyclist is 
.
Explanation:
speed of cyclist = 12 km/h east
speed of wind = 5 km/h south west
Write the speeds in the vector form
The velocity of wind with respect to cyclist is
I believe it's DNA.
Here're some sentences to explain:
Genetic material, also known as deoxyribonucleic acid<span> (</span>DNA<span>) and </span>Ribonucleic acid<span> (</span>RNA<span>), plays a fundamental role in the composition of living organisms.</span>
Answer:
When a moving bus stops suddenly, the passenger are pushed forward because of the inertia of the passengers. ... Because the lower part of the body comes to rest with the bus while the upper part tends to continue its motion due to inertia.
Explanation :
The passengers in a bus tend to fall backward when it starts suddenly due to inertia as the passengers tend to remain in the state of rest while the bus starts to move. When the bus stops suddenly, people fall forward because their inertia as they are in state of motion even when the bus has come to rest.
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When the mass is 5.0 cm from its equilibrium point, the percentage of its energy that is kinetic is 75%.
<h3>Total energy of the mass</h3>
The total energy possessed by the mass under the simple harmonic motion is calculated as follows;
U = ¹/₂kA²
where;
- k is the spring constant
- A is the amplitude of the oscillation
<h3>Potential energy of the mass at 5 cm from equilibrium point</h3>
P.E = ¹/₂k(Δx)²
<h3>Kinetic energy of mass</h3>
K.E = U - P.E
K.E = ¹/₂kA² - ¹/₂k(Δx)²
<h3>Percentage of its energy that is kinetic</h3>
Thus, when the mass is 5.0 cm from its equilibrium point, the percentage of its energy that is kinetic is 75%.
Learn more about kinetic energy here: brainly.com/question/25959744
