Answer:
i assume the system is in equilibrium
Explanation:
(W_p-T)(2)+W_b(2.5)= T(sin 45 degrees)(5)
T(((sin 45 degrees)(5)) + 2) = (W_p)(2) + W_b(2.5)= T(5.5355)
Answer:150Nm
Explanation:
Force=50.0N distance=3.00m
Work=force x distance
Work=50 x 3
Work=150Nm
Answer:
v = 22.68 10⁻³ m / s
vₓ = 5.32 10⁻³ m / s
, v_{y} = 22.08 10⁻³ m / s
Explanation:
Velocity is defined by
v = Δs / Δt
let's calculate for each axis
X axis
vₓ = (3.07 - 1.33) / 327
vₓ = 5.32 10⁻³ m / s
Y axis
= (4.33 - (- 2.89)) / 327
v_{y} = 22.08 10⁻³ m / s
the magnitude of the velocity can be calculated using the Pythagoras theorem
v² = vₓ² + v_{y}²
v = √ (vₓ² + v_{y}²)
v = √ (5.32² + 22.05²) 10⁻³
v = 22.68 10⁻³ m / s
Answer:
W = 1750 J
Explanation:
It is given that,
Weight of a computer, F = 50 N
A student wants to keep it on the 5th floor which is 35 meters up.
We need to find the work done by her to drag her computer up the stairs. Let it is W. Using the formula of work as follows :
W = F d
Put all the values,
W = 50 N × 35 m
W = 1750 J
So, 1750 J of work is done by her to drag the computer up the stairs.
Tossing an object into the bin , you got some force applied on the object after which it will go into an projectile motion